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lianna [129]
3 years ago
13

What is physiography ? ​

Chemistry
1 answer:
Alexxandr [17]3 years ago
8 0

Answer:

Physical geography is one of the two fields of geography. Physical geography is the branch of natural science which deals with the processes and patterns in the natural environment such as the atmosphere

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USPshnik [31]

the water is heated until it evaporates

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Which statement is not true regarding nuclear reactions? Alpha, beta, and gamma are types of radiation. Nuclear reactions involv
svet-max [94.6K]
Alpha I believe not sure
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How much is one liter
Bas_tet [7]

Answer:

1 litre = 1000 millilitres

8 0
3 years ago
When 136g of glycine are dissolved in of a certain mystery liquid , the freezing point of the solution is lower than the freezin
loris [4]

The given question is incomplete. The complete question is:

When 136 g of glycine are dissolved in 950 g of a certain mystery liquid X, the freezing point of the solution is 8.2C lower than the freezing point of pure X. On the other hand, when 136 g of sodium chloride are dissolved in the same mass of X, the freezing point of the solution is 20.0C lower than the freezing point of pure X. Calculate the van't Hoff factor for sodium chloride in X.

Answer: The vant hoff factor for sodium chloride in X is 1.9

Explanation:

Depression in freezing point is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=T_f^0-T_f=8.2^0C = Depression in freezing point

K_f = freezing point constant

i = vant hoff factor = 1 ( for non electrolyte)

m= molality =\frac{136g\times 1000}{950g\times 75.07g/mol}=1.9

8.2^0C=1\times K_f\times 1.9

K_f=4.32^0C/m

Now Depression in freezing point for sodium chloride is given by:

\Delta T_f=i\times K_f\times m

\Delta T_f=20.0^0C = Depression in freezing point

K_f = freezing point constant  

m= molality = \frac{136g\times 1000}{950g\times 58.5g/mol}=2.45

20.0^0C=i\times 4.32^0C\times 2.45

i=1.9

Thus vant hoff factor for sodium chloride in X is 1.9

3 0
3 years ago
If I have 12.0 volume of gas at pressure of 1.10 and temperature of 200k, what is the number of moles? (R=8314)
arsen [322]

Answer:

7.94 x 10^6 mol

Explanation:

PV=nRT

n=(PV)/(RT)

n=(1.10*12.0)/(8314*200)

n=7.94 x 10^6 mol

5 0
3 years ago
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