7x+y=11 where y= -5 So, when we substitute y in the equation then,
7x + (-5) = 11 that is 7x - 5 = 11....
So, B. is the right answer.
Answer:

Step-by-step explanation:
Draw a diagonal (line segment from one corner to the opposite corner). You'll form two right triangles with the diagonal being the hypotenuse of both triangles.
Use the Pythagorean Theorem: (leg)^2 + (leg)^2 = (hypotenuse)^2.
Let h represent the length of the hypotenuse.

The question is just a bit vague. It should say opposite corners. I'm assuming the question does not mean the length of one side!
You solve this by plugging one equation into the other. Usually you have to rewrite one equation to make this work. In this case I choose to rewrite y-4x=0 as y=4x.
After plugging it into the second, you get:
3x + 6*4x = 9 => 27x = 9 => x=1/3
Putting this solution back into y=4x gives us y=4/3
C. negative exponents always go at the bottom