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Tanzania [10]
2 years ago
9

A babysitter charges a rate of $15 per hour. how long was the babysitter there if she makes $5

Mathematics
1 answer:
Anika [276]2 years ago
6 0

Answer:

20 mins.

Step-by-step explanation:

A babysitter charges a rate of $15 per hour. How long was the babysitter there if she makes $5?

x = hours she babysat

Equation:

15x = 5

Divide to isolate x:

15x = 5

/15   /15

x = 1/3 hrs.

Now, we convert into minutes, since she didn't work for a whole hour, to earn the $15

We know that there are 60 mins. in an hour

60 * 1/3

60/3

20 mins.

Therefore, the babysitter was there for 20 mins.

Hope this helps!

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The floor of a triangular room has an area of 32 1/2 sq.m. If the triangle’s altitude is 7 172 m, write an equation to determine
sineoko [7]

Answer:

\frac{(2)A}{h} =b

b=0.00906m

Step-by-step explanation:

Hello! To solve this exercise we must remember that the area of ​​any triangle is given by the following equation

A=\frac{bh}{2}

where

A=area=32.5m^2

h=altitude=7172m

b=base

Now what we should do take the equation for the area of ​​a rectangle and leave the base alone, remember that what we do on one side of the equation we must do on the other side to preserve equality

A=\frac{bh}{2} \\\frac{2}{h} A=\frac{bh}{2} \frac{2}{h} \\

\frac{A(2)}{h} =b

solving

\frac{2(32.5)}{7172} =0.0090[tex]\frac{A(2)}{h} =b\\b=0.00906m

4 0
3 years ago
What is the prime factorization of 100 using exponent's?
makkiz [27]

Answer:

The Prime Factorization is:

2 x 2 x 5 x 5

In Exponential Form:

22 x 52

CSV Format:

2, 2, 5, 5

6 0
3 years ago
15. Suppose a box of 30 light bulbs contains 4 defective ones. If 5 bulbs are to be removed out of the box.
Naddika [18.5K]

Answer:

1) Probability that all five are good = 0.46

2) P(at most 2 defective) = 0.99

3) Pr(at least 1 defective) = 0.54

Step-by-step explanation:

The total number of bulbs = 30

Number of defective bulbs = 4

Number of good bulbs = 30 - 4 = 26

Number of ways of selecting 5 bulbs from 30 bulbs = 30C5 = \frac{30 !}{(30-5)!5!} \\

30C5 = 142506 ways

Number of ways of selecting 5 good bulbs  from 26 bulbs = 26C5 = \frac{26 !}{(26-5)!5!} \\

26C5 = 65780 ways

Probability that all five are good = 65780/142506

Probability that all five are good = 0.46

2) probability that at most two bulbs are defective = Pr(no defective) + Pr(1 defective) + Pr(2 defective)

Pr(no defective) has been calculated above = 0.46

Pr(1 defective) = \frac{26C4  * 4C1}{30C5}

Pr(1 defective) = (14950*4)/142506

Pr(1 defective) =0.42

Pr(2 defective) =  \frac{26C3  * 4C2}{30C5}

Pr(2 defective) = (2600 *6)/142506

Pr(2 defective) = 0.11

P(at most 2 defective) = 0.46 + 0.42 + 0.11

P(at most 2 defective) = 0.99

3) Probability that at least one bulb is defective = Pr(1 defective) +  Pr(2 defective) +  Pr(3 defective) +  Pr(4 defective)

Pr(1 defective) =0.42

Pr(2 defective) = 0.11

Pr(3 defective) =  \frac{26C2  * 4C3}{30C5}

Pr(3 defective) = 0.009

Pr(4 defective) =  \frac{26C1  * 4C4}{30C5}

Pr(4 defective) = 0.00018

Pr(at least 1 defective) = 0.42 + 0.11 + 0.009 + 0.00018

Pr(at least 1 defective) = 0.54

3 0
3 years ago
A ball is thrown into the air from a height of 4 feet at time t = 0. The function that models this situation is h(t) = -16t2 + 6
katrin2010 [14]

Answer:

Part a) The height of the ball after 3 seconds is 49\ ft

Part b) The maximum height is 66 ft

Part c) The ball hit the ground for t=4 sec

Part d) The domain of the function that makes sense is the interval

[0,4]

Step-by-step explanation:

we have

h(t)=-16t^{2} +63t+4

Part a) What is the height of the ball after 3 seconds?

For t=3 sec

Substitute in the function and solve for h

h(3)=-16(3)^{2} +63(3)+4=49\ ft

Part b) What is the maximum height of the ball? Round to the nearest foot.

we know that

The maximum height of the ball is the vertex of the quadratic equation

so

Convert the function into a vertex form

h(t)=-16t^{2} +63t+4

Group terms that contain the same variable, and move the constant to the opposite side of the equation

h(t)-4=-16t^{2} +63t

Factor the leading coefficient

h(t)-4=-16(t^{2} -(63/16)t)

Complete the square. Remember to balance the equation by adding the same constants to each side

h(t)-4-16(63/32)^{2}=-16(t^{2} -(63/16)t+(63/32)^{2})

h(t)-(67,600/1,024)=-16(t^{2} -(63/16)t+(63/32)^{2})

Rewrite as perfect squares

h(t)-(67,600/1,024)=-16(t-(63/32))^{2}

h(t)=-16(t-(63/32))^{2}+(67,600/1,024)

the vertex is the point (1.97,66.02)

therefore

The maximum height is 66 ft

Part c) When will the ball hit the ground?

we know that

The ball hit the ground when h(t)=0 (the x-intercepts of the function)

so

h(t)=-16t^{2} +63t+4

For h(t)=0

0=-16t^{2} +63t+4

using a graphing tool

The solution is t=4 sec

see the attached figure

Part d) What domain makes sense for the function?

The domain of the function that makes sense is the interval

[0,4]

All real numbers greater than or equal to 0 seconds and less than or equal to 4 seconds

Remember that the time can not be a negative number

6 0
3 years ago
Is 7/20 and 0.07 equivalent numbers
IceJOKER [234]
\frac{7}{20}=0.35 \\ 
 \\  \frac{7}{100}=0.07 \\ 
 \\ Solution: No \ they \ are \ not \ equivalent \ fractions \\
7 0
3 years ago
Read 2 more answers
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