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Nataly_w [17]
3 years ago
10

If you push a chair across the floor at a constant velocity, how does the force of friction compare with the force you exert? ex

plain.
Physics
1 answer:
patriot [66]3 years ago
6 0
If the velocity of the chair is constant, then the net force acting on it is zero.

The force you exert to keep it going is equal and opposite to the force of friction.
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Classify:Energyis the ability to exert force and cause change. Energy has manyforms:
Grace [21]

Answer:

Energy: Kinetic, Sound, Thermal, gravitational, electric, light and nuclear

Explanation:

This exercise asks to clarify a little some important concepts

* Energy. It is the capable one that has the bodies to carry out a job.

* Kinetic energy. It is the energy due to the movement of objects

* sound energy. It is the energy due to the vibration of the atoms or molecules of the materials, it can be solid, liquid or gaseous

* Thermal energy. It is the energy due to movement of the particles

* Gravitational Energy. It is a configuration energy due to the height of the bodies with respect to a reference point

* Electric power. It is due to the movement of electric charges

* light energy. It is the energy that light carries due to the electric and magnetic fields that form it, it occurs throughout the electromagnetic spectrum

* Nuclear energy. It is the energy stored in the nucleus by the configuration and movement of protons and neutrons.

6 0
3 years ago
A skater goes into a spin with her arms pulled in (close to her body). When she stretches her arms out: A) her angular speed ω d
musickatia [10]

Answer:

When she stretches her arms out,<em> B) her angular speed ω increases due to her moment of inertia decreasing</em>

Explanation:

The angular momentum of a rotating object is defined as the product of its moment of inertia and angular speed.

<em>L = I ω</em>

<em>where</em>

  • <em>L is the angular momentum</em>
  • <em>I is the moment of inertia</em>
  • <em>ω is the angular speed</em>

<em />

According to the principle of conservation of angular momentum, if there is no external torque, angular momentum of the skater must remain conserved. If the initial and final moment of inertia is <em>I_i and I_f  </em>while corresponding angular velocities are <em>ω_i and ω_f , </em>then the principle of conservation of angular momentum can be expressed as the following equation:

<em>(I_f) (ω_f) = (I_i) (ω_i)</em>

<em>ω_f / ω_i = I_i / I_f</em>

<em />

From the expression above, we can see that if the moment of inertia decreases, angular velocity would increase to conserve angular momentum of the skater.

Therefore, When she stretches her arms out,<em> her angular speed ω increases due to her moment of inertia decreasing.</em>

5 0
4 years ago
Please answer ASAP!!
ch4aika [34]

Answer:

O So you can ask questions about steps you do not understand.

Explanation:

One of the reasons why it is encouraged that the laboratory procedure must be read at the beginning of any type of experiment is familiarize the student with the experimental procedure. Also, questions that can help make the smooth running of the experiment to proceed can be cleared.

  • It is to this regard that understanding laboratory procedures is very vital.
  • Students must grasp the details of each steps of the experiment before proceeding with their investigation.
  • Other critical information needed to set up the experiment can also be brought into the lime light.
3 0
3 years ago
Who got the energy conversation in a system gizmo answers dm me on insta .al3xgonrockout​
Mars2501 [29]

Answer:

a

Explanation:

3 0
3 years ago
Let's say you are on the third story of an apartment building that has a swimming pool. For some insane reason you think it is a
labwork [276]

Answer:

To make it into the pool you must run and jump at

\displaystyle v_o=x.\sqrt{\frac{g}{2y}}

Explanation:

Horizontal Launch

When an object is thrown with a specified initial speed in the horizontal direction, it describes a curved path that finishes when it hits the ground level after traveling certain horizontal distance x and a vertical height y from the launching point. The horizontal speed is always constant and the vertical speed increases due to the effect of gravity. It can be found that the horizontal distance reached by the object when launched at an initial speed  in a given time t is

x=v_o.t

And the vertical distance is

\displaystyle y=\frac{g.t^2}{2}

If t is the total flight time, then x and y are maximum and we can find a relation between them. Solving for t in the first equation

\displaystyle t=\frac{x}{v_o}

Substituting in the second equation

\displaystyle y=\frac{g}{2}\left ( \frac{x}{v_o}\right )^2

Rearranging

\displaystyle \left ( \frac{v_o}{x}\right )^2=\frac{g}{2y}

Solving for v_o

\displaystyle v_o=x.\sqrt{\frac{g}{2y}}

There are many applications for the horizontal launch. One common situation is when someone wants to drop something on certain terrain at a specific approximate point when traveling in a plane at a given height. Once the object is left fall, it has the same speed as the plane, so the plane speed can be estimated to make the best possible launch, or given that speed, we can know in advance where the object will reach ground level

4 0
3 years ago
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