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klio [65]
2 years ago
5

The deepest section of ocean in the world is the Marianas Trench, located in the Pacific Ocean. Here the ocean floor is as low a

s 10,918 m below the surface. The index of refraction of water is 1.33. Calculate the time for the laser beam to reach the bottom of the trench
Physics
1 answer:
Levart [38]2 years ago
3 0
B I just took the test
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An object, initially at rest, is subject to an acceleration of 34 m/s^2. How long will it take for that object to reach 3400m ?
Norma-Jean [14]
Vf^2 = Vi^2 + 2ad
a= 34 m/s^2
Vi = 0 m/s
d = 3400m

Vf = 480.83 m/s

a=v/t
t=v/a
t=480.83/34
t=14.142 s
6 0
3 years ago
How do your results from ray tracing compare to your results from using the thin-lens equation?
EastWind [94]

Answer:

20cm

Explanation:

A convex lens has a positive focal length and the object placed in front of it produce both virtual and real image <em>(image distance can be negative or positive depending on the nature of the image</em>).

According to the lens equation

\frac{1}{f} = \frac{1}{u} + \frac{1}{v} where;

f is the focal length  of the lens

u is the object distance

v is the image distance

If the magnification is - 0.6

mag = v/u = -0.5

v = -0.5u

since v = 10cm

10 = -0.5u

u = -10/0.5

u =-20 cm

Substitute u = -20cm ( due to negative magnification)and v = 10cm into the lens formula to get the focal length f

\frac{1}{f} = \frac{1}{u} + \frac{1}{v}\\\frac{1}{f} = \frac{1}{-20} + \frac{1}{10}\\\frac{1}{f} = \frac{1}{-20} + \frac{1}{10}\\\frac{1}{f} = \frac{-1+2}{20} \\\frac{1}{f} = \frac{1}{20} \\cross \ multiply\\f = 20\\f = 20 cm

Hence the focal length of the convex lens is 20cm

7 0
3 years ago
What is the velocity of a 2000 kg truck with a momentum of 48,000 kg•m/s?
Goshia [24]

Answer:

24

Explanation:

momentum= mass* velocity

velocity= momentum/ mass

5 0
3 years ago
With the switch open, roughly what must be the resistance of the resistor on the right for the current out of the battery to be
Delvig [45]

Answer:

The resistance must be 6.67\Omega

Solution:

Resistance, R_{1} = 20\Omega

Resistance, R_{2} = 10\Omega

For the current to be the same when the switch is open or closed, the resistances must be connected in parallel as current is distributed in parallel with the same voltage across the circuit:

Thus in parallel:

\frac{1}{R_{eq}} = \frac{1}{R_{1}} + \frac{1}{R_{2}}

\frac{1}{R_{eq}} = \frac{1}{20} + \frac{1}{10}

R_{eq} = 6.67\ \Omega

4 0
3 years ago
Can someone help me with these questions please. I will mark brainliest
VladimirAG [237]

Answer:

3: I can´t see the text/image, but it depend on the mass and the force applied to the ball, if both are too high, it will be harder to make a home run. (Second law)

4:It would be easier to make a home run because there is no interruption between the ball and the space the same travels. (Third law)

Explanation:

3 0
3 years ago
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