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Tju [1.3M]
4 years ago
7

What is a cell?

Chemistry
1 answer:
Nikitich [7]4 years ago
4 0

the answer 2 dat prob is #2

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What element s a halgen gas with a mass les than 19
dalvyx [7]
The halogens are Group 7. Group 7 consists of Flourine, Chlorine, Bromine, Iodine and Astatine.

Element Mass

Flourine 18.99
Chlorine. 35.5
Bromine. 79.9
Iodine. 126.9
Astatine 210

The answer is Flourine because it has a mass of less than 19 :) Hope this helps.
4 0
3 years ago
At room temperature and pressure, 0.4 g of neon will occupy what volume<br> of gas?
LekaFEV [45]

Answer:

"One mole of any gas has a volume of 24 dm3 or 24,000 cm3 at rtp (room temperature and pressure). This volume is called the molar volume of a gas."

Explanation:

Divide the mass of neon.

8 0
3 years ago
Help 15 points!!!<br> Complete the following combustion reaction.
Allushta [10]

Answer:

C₈H₁₈ + 25/2O₂ —> 8CO₂ + 9H₂O

2C₈H₁₈ + 25O₂ —> 16CO₂ + 18H₂O

Explanation:

The reaction above is simply termed combustion reaction in which an organic compound react with oxygen to produce carbon dioxide and water. Thus, we can obtain the balanced equation for the reaction reaction as follow:

C₈H₁₈ + O₂ —> CO₂ + H₂O

There are 8 atoms of C on the left side and 1 atom on the right side. It can be balance by writing 8 before CO₂ as shown below:

C₈H₁₈ + O₂ —> 8CO₂ + H₂O

There are 18 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 9 before H₂O as shown below:

C₈H₁₈ + O₂ —> 8CO₂ + 9H₂O

There are 2 atoms of O on the left side and a total of 25 atoms on the right side. It can be balance by writing 25/2 before O₂ as shown below:

C₈H₁₈ + 25/2O₂ —> 8CO₂ + 9H₂O

Thus, the equation is balanced!

The above equation can also be written as follow:

C₈H₁₈ + 25/2O₂ —> 8CO₂ + 9H₂O

Multiply through by 2

2C₈H₁₈ + 25O₂ —> 16CO₂ + 18H₂O

4 0
3 years ago
Clarity of signal
bija089 [108]
Digital offers better clarity,but analog gives you richer quality
5 0
3 years ago
Read 2 more answers
What does biodiversity mean?
kobusy [5.1K]

Answer:

Having as wide a range of organisms as possible.

Hope it helps! :)

7 0
3 years ago
Read 2 more answers
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