The answer is 84.00661 grams
I think the answer is A. 28 because you add 27 + 1 = 28 and add the 13AL and makes 2813AL
I Hope Its Helps
<h3>
Answer:</h3>
56.11 g/mol
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
[Compound] KOH
<u>Step 2: Identify</u>
[PT] Molar Mass of K - 39.10 g/mol
[PT] Molar Mass of O - 16.00 g/mol
[PT] Molar Mass of H - 1.01 g/mol
<u>Step 3: Find</u>
39.10 + 16.00 + 1.01 = 56.11 g/mol
Answer:
= 55.7g
Explanation:
12g of carbon burnt to produce 5x10^2KJ
So, 5x10^2KJ(12g/393.5KJ)=15.2g
Then mas of CO2 is 44g
So, 15.2g(12g/44g)=57.7g
The molarity of potassium ions in a 0.122 M K2CrO4 is 0.244 M
<u><em>Explanation</em></u>
write dissociation reaction for K2CrO4
that K2CrO4 (aq)→ 2K^+ (aq) + CrO4^2- (aq)
K2CrO4 dissociate to give 2 ions of potassium ,therefore the molarity of potassium ion = 2 x 0.122 = 0.244 M