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NeTakaya
3 years ago
13

Factors that control Traits are called

Chemistry
1 answer:
irina [24]3 years ago
7 0

Answer:

genes

Explanation:

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One application of Hess's Law (which works for ΔH, ΔS, and ΔG) is calculating the overall energy of a reaction using standard en
VikaD [51]

Answer:

The standard change in free energy for the reaction =  - 437.5 kj/mole

Explanation:

The standard change in free energy for the reaction:

                              4 KClO₃ (s) → 3 KClO₄(s) + KCl(s)

Given that   ΔGf(KClO3(s)) = -290.9 kJ/mol;

                    ΔGf(KClO4(s)) = -300.4 kJ/mol;

                    ΔGf(KCl(s)) = -409 kJ/mol

According to Hess's law

ΔGr (Free energy change of reaction)= ∑(Product free energy - reactant free energy)

               ⇒ ΔGr⁰ = {3 x (-300.4) + (-409)} - {3 x (- 290.9)}

                            = - 901.2 - 409 + 872.7

                            =  - 437.5 kj/mole

3 0
3 years ago
Which of the following is not a catalyst? A. Nickel B. Platinum C. Enzymes D. Phosphorus
Mazyrski [523]
The answer would be D because from my research it's the only one that didn't have a catalyst 
6 0
3 years ago
Read 2 more answers
What is the net ion charge of Beryllium?​
KATRIN_1 [288]

Explanation:

Beryllium is a group 2 element and its atomic number is 4. Electronic configuration of beryllium is 1s^{2}2s^{2}.

Since, a beryllium contains two valence electrons so, in order to attain stability it will readily lose its 2 valence electrons.

Therefore, a beryllium atom upon losing two valence electrons will acquire a +2 charge.

Thus, we can conclude that the net ion charge of Beryllium is +2.

7 0
3 years ago
The moon makes light the same way that the sun does.True or False
lesya [120]

Answer: false

Explanation:

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3 years ago
Question 2: Heat (5 points)
Ronch [10]

Answer:

(i) specific heat

(ii) latent heat of vaporization

(iii) latent heat of fusion

Explanation:

i. Q = mcΔT; identify c.

Here, Q is heat, m is the mass, c is the specific heat and ΔT is the change in temperature.

The amount of heat required to raise the temperature of substance of mass 1 kg by 1 degree C is known as the specific heat.  

ii. Q = mLvapor; identify Lvapor

Here, Q is the heat, m is the mass and L is the latent heat of vaporization.

The amount of heat required to convert the 1 kg liquid into 1 kg vapor at constant temperature.  

iii. Q = mLfusion; identify Lfusion

Here, Q is the heat, m is the mass and L is the latent heat of fusion.  

Here, Q is the heat, m is the mass and L is the latent heat of vaporization.

The amount of heat required to convert the 1 kg solid  into 1 kg liquid at constant temperature.  

8 0
3 years ago
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