Answer:
![320 = 10 (2)^{t/60}](https://tex.z-dn.net/?f=%20320%20%3D%2010%20%282%29%5E%7Bt%2F60%7D)
If we divide both sides by 10 we got:
![32 = 2^{t/60}](https://tex.z-dn.net/?f=%2032%20%3D%202%5E%7Bt%2F60%7D)
We can apply natural log on both sides and we got:
![ln (32) = \frac{t}{60} ln(2)](https://tex.z-dn.net/?f=%20ln%20%2832%29%20%3D%20%5Cfrac%7Bt%7D%7B60%7D%20ln%282%29%20)
And solving the value of t we got:
![t = 60 \frac{ln(32)}{ln(2)}= 300](https://tex.z-dn.net/?f=%20t%20%3D%2060%20%5Cfrac%7Bln%2832%29%7D%7Bln%282%29%7D%3D%20300)
So then we can conclude that after t = 300 days we will have approximately 320 rabbits
Step-by-step explanation:
For this case we have the following function:
![P(t) = 10 (2)^{t/60}](https://tex.z-dn.net/?f=%20P%28t%29%20%3D%2010%20%282%29%5E%7Bt%2F60%7D)
Where P is the population of rabbis on day t. And for this case we want to find the value of t when P =320 so we can set up the following equation:
![320 = 10 (2)^{t/60}](https://tex.z-dn.net/?f=%20320%20%3D%2010%20%282%29%5E%7Bt%2F60%7D)
If we divide both sides by 10 we got:
![32 = 2^{t/60}](https://tex.z-dn.net/?f=%2032%20%3D%202%5E%7Bt%2F60%7D)
We can apply natural log on both sides and we got:
![ln (32) = \frac{t}{60} ln(2)](https://tex.z-dn.net/?f=%20ln%20%2832%29%20%3D%20%5Cfrac%7Bt%7D%7B60%7D%20ln%282%29%20)
And solving the value of t we got:
![t = 60 \frac{ln(32)}{ln(2)}= 300](https://tex.z-dn.net/?f=%20t%20%3D%2060%20%5Cfrac%7Bln%2832%29%7D%7Bln%282%29%7D%3D%20300)
So then we can conclude that after t = 300 days we will have approximately 320 rabbits
For question (ii) I'm not sure if the answer is correct or not because I don't understand the question asked ...
I hope I can help ....
You can take out a 3x and get (3x)2x^4+3x^2-9
Which question?
How can I answer if I don't know the question
Answer: acute 90-
Step-by-step explanation: