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2 years ago

Please helpSelect all of the non-real complex numbers in the given table.

Mathematics

1 answer:

Alex17521 [72]2 years ago

8 0

Answer:

All the expressions that have a negative in the radical

(Boxes 2, 3 5, and 6)

Step-by-step explanation:

You can't take the square root of a negative number. When you square a number, the product will always be positive.

Hope this helps!

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Please need help with this math question

fenix001 [56]

X=15

Hope this helps!!!

3 0

3 years ago

Y=-3x+3/4 what is the slope and y intercept

Len [333]

Answer:

the slope is equal to m or in this case 3. the y intercept is equal to b or 3/4

Step-by-step explanation:

8 0

3 years ago

#24, i am getting <img src="https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%260%260%26%5Cfrac%7B18%7D%7B7%7D%20

sveticcg [70]

It looks like you're talking about row-reducing an augmented matrix to solve the system of equations. Your answer is almost correct. The last row should read 0, 0, 1, 2/7.

The given system translates to

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 1 & -1 & 2 & 2 \\ 1 & 2 & -3 & 4 \end{array} \right]$

Eliminate x from the last two rows by combining -2 (row 2) and row 1, and -2 (row 3) and row 1; that is,

(2x - 3y + z) - 2 (x - y + 2z) = 2 - 2 (2)

2x - 3y + z - 2x + 2y - 4z = 2 - 4

-y - 3z = -2

and

(2x - 3y + z) - 2 (x + 2y - 3z) = 2 - 2 (4)

2x - 3y + z - 2x - 4y + 6z = 2 - 8

-7y + 7z = -6

In augmented matrix form, this step yields

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & -3 & -2 \\ 0 & -7 & 7 & -6 \end{array} \right]$

I'll omit these details in the remaining steps.

Eliminate y from the last row by combining -7 (row 2) and row 3 :

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & -3 & -2 \\ 0 & 0 & 28 & 8 \end{array} \right]$

Multiply the last row by 1/28 :

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & -3 & -2 \\ 0 & 0 & 1 & 2/7 \end{array} \right]$

Eliminate z from the second row by combining 3 (row 3) and row 2 :

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & -1 & 0 & -8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]$

Multiply the second row by -1 :

$\left[ \begin{array}{ccc|c} 2 & -3 & 1 & 2 \\ 0 & 1 & 0 & 8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]$

Eliminate y and z from the first row by combining 3 (row 2), -1 (row 3), and row 1 :

$\left[ \begin{array}{ccc|c} 2 & 0 & 0 & 36/7 \\ 0 & 1 & 0 & 8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]$

Multiply the first row by 1/2 :

$\left[ \begin{array}{ccc|c} 1 & 0 & 0 & 18/7 \\ 0 & 1 & 0 & 8/7 \\ 0 & 0 & 1 & 2/7 \end{array} \right]$

8 0

3 years ago

Write a compound inequality for the following statement:

iren2701 [21]

Answer:

-42 ≤ x ≤ 102

Step-by-step explanation:

Compound from the fact that we're combining x≤42 and x≤102.

5 0

3 years ago

Read 2 more answers

4(x+1.5)=38 solve for x

Kitty [74]

Answer:

x = 8

Step-by-step explanation:

4(x+1.5)=38

Distribute the 4

4x +6 = 38

Subtract 6 from each side

4x+6-6 = 38-6

4x = 32

Divide each side by 4

4x/4 = 32/4

x = 8

3 0

4 years ago

Please helpSelect all of the non-real complex numbers in the given table.​

Please helpSelect all of the non-real complex numbers in the given table.