The answer is A supplementary Angle
Log xy/4 =
log xy - log 4 =
log x + log y - log 4
Answer:
Ix = Iy =
Radius of gyration x = y = 
Step-by-step explanation:
Given: A lamina with constant density ρ(x, y) = ρ occupies the given region x2 + y2 ≤ a2 in the first quadrant.
Mass of disk = ρπR2
Moment of inertia about its perpendicular axis is
. Moment of inertia of quarter disk about its perpendicular is
.
Now using perpendicular axis theorem, Ix = Iy =
=
.
For Radius of gyration K, equate MK2 = MR2/16, K= R/4.
Answer:
The perimeter is 99
Step-by-step explanation:
you do 11x9=99
Answer:
24
Step-by-step explanation: