About 4 C to for water density until it is cooled
Answer:

Explanation:
We are given the amounts of two reactants, so this is a limiting reactant problem.
1. Assemble all the data in one place, with molar masses above the formulas and other information below them.
Mᵣ: 58.44
NaCl + AgNO₃ ⟶ NaNO₃ + AgCl
m/g: 0.245
V/mL: 50.
c/mmol·mL⁻¹: 0.0180
2. Calculate the moles of each reactant

3. Identify the limiting reactant
Calculate the moles of AgCl we can obtain from each reactant.
From NaCl:
The molar ratio of NaCl to AgCl is 1:1.

From AgNO₃:
The molar ratio of AgNO₃ to AgCl is 1:1.

AgNO₃ is the limiting reactant because it gives the smaller amount of AgCl.
4. Calculate the moles of excess reactant
Ag⁺(aq) + Cl⁻(aq) ⟶ AgCl(s)
I/mmol: 0.900 4.192 0
C/mmol: -0.900 -0.900 +0.900
E/mmol: 0 3.292 0.900
So, we end up with 50. mL of a solution containing 3.292 mmol of Cl⁻.
5. Calculate the concentration of Cl⁻
![\text{[Cl$^{-}$] } = \dfrac{\text{3.292 mmol}}{\text{50. mL}} = \textbf{0.066 mol/L}\\\text{The concentration of chloride ion is $\large \boxed{\textbf{0.066 mol/L}}$}](https://tex.z-dn.net/?f=%5Ctext%7B%5BCl%24%5E%7B-%7D%24%5D%20%7D%20%3D%20%5Cdfrac%7B%5Ctext%7B3.292%20mmol%7D%7D%7B%5Ctext%7B50.%20mL%7D%7D%20%3D%20%5Ctextbf%7B0.066%20mol%2FL%7D%5C%5C%5Ctext%7BThe%20concentration%20of%20chloride%20ion%20is%20%24%5Clarge%20%5Cboxed%7B%5Ctextbf%7B0.066%20mol%2FL%7D%7D%24%7D)
1 mol ------- 6,02·10²³
X ------------ 3,98·10²³
X = 3,98·10²³/<span>6,02·10²³
<u>X= 0,6611</u> moles of oxygen
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Answer:
Higher pH (more alkaline)
Explanation:
The pH scale measures on a scale of 0 to 14 the acidity or basicness of whatever is being tested.
The lower the pH, the more acidic it will be. Acids are scaled as being anything having a pH of lower than 7.
The higher the pH, the more alkaline (or basic) it will be. Bases are scaled as being anything having a pH of higher than 7.
Substances that are at a pH of 7 are considered neutral, like water (H2O)
You multiply 32 by 2, since there are two hydrogens in every water molecule.