Scientists often repeat one or more steps several times.
Answer:
Spectrum 1- Biphenyl
Spectrum 2 - Benzil
Spectrum 3 - Bibenzyl
Explanation:
<u>For Benzil:
</u>
<u>
</u>The Spectrum - 2 shows this compound.The C=O and C-H bond stretching observed at following values.


<u> For Biphenyl:
</u>
<u>
</u>Spectrum - 1 shows this compound.
There are stretching vibrations from
due to C-H stretching and C-C stretching respectively of aromatic ring only.
<u>For Bibenzyl:
</u>
Spectrum - 3 shows this compound
There are stretching vibrations at
due to C-H stretching and C-C stretching of aromatic ring.
Along with this, stretching vibrations at
due to C-H of alkyl.
Answer:
carbon and silicon
Explanation:
Various groups of elements in the periodic table have different outermost shell electron configurations. Actually, elements are classified into groups on the basis of the number of electrons on the outermost shell of those elements. All elements with the same number of electrons on their outermost shell belong to the same group in the periodic table.
For elements in group 14, they all have four electrons on their outermost shell. Their general outer electron configuration is ns2 np2 as shown in the question. Two prominent members of this group are carbon and silicon. This ns2 np2 is the ground state outer electron configuration of all group 14 elements in the periodic table.
Answer:
equilibrium will shift to the right, and more NH3 will be formed
Explanation:
N2(g) + 3H2(g) ---> 2NH3(g)
1 mol +3 mol 2 mol
4 mol 2 mol
When we increase the pressure, the pressure will try to restore old value, so it has to become lower. Pressure is lower when number of particles is less
4 <2, so equilibrium will shift to the right, and more NH3 will be formed.
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