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Drupady [299]
2 years ago
11

There is an extreme temperature difference between day and night in a desert during clear weather. However, even though the outs

ide temperature drops greatly at night, the water in a swimming pool in the desert tends to remain warm. Use your knowledge of heat energy, specific heat, and heat transfer to explain these facts.
please help!!!!!! ​
Chemistry
1 answer:
den301095 [7]2 years ago
5 0

Sand has a lower heat capacity hence it heats up easily and looses heat easily. On the other hand, water has a higher heat capacity and looses heat more slowly hence it remains warm at night.

<h3>What is heat transfer?</h3>

The transfer of heat refers to the movement of heat from one body to another. We should note that sand has a low specific heat capacity hence it is rapidly heated up in the day and looses heat quickly at night.

On the other hand, water has a high specific heat capacity hence it heat up slowly and also does not loose heat easily even when the surrounding temperature is much colder. As such, there is an extreme temperature difference between day and night in a desert during clear weather and the water in a swimming pool in the desert tends to remain warm even when the outside temperature drops greatly at night.

Learn more about heat transfer: brainly.com/question/12107378

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Answer:

Iron remains = 17.49 mg

Explanation:

Half life of iron -55 = 2.737 years (Source)

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac {ln\ 2}{t_{1/2}}

k=\frac {ln\ 2}{2.737}\ year^{-1}

The rate constant, k = 0.2533 year⁻¹

Time = 2.41 years

[A_0] = 32.2 mg

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

So,  

[A_t]=32.2\times e^{-0.2533\times 2.41}\ mg

[A_t]=32.2\times e^{-0.610453}\ mg

[A_t]=17.49\ mg

<u>Iron remains = 17.49 mg</u>

8 0
3 years ago
Imagine you had HCl with a concentration of exactly 0.10 mol/dm3. If 0.023 dm3 of a sodium hydroxide solution, NaOH (aq), could
polet [3.4K]

Answer:

Explanation:

Step 1: Calculate the amount of sodium hydroxide in moles

Volume of sodium hydroxide solution = 25.0 ÷ 1,000 = 0.0250 dm3

Rearrange:

Concentration in mol/dm3 =

Amount of solutein mol = concentration in mol/dm3 × volume in dm3

Amount of sodium hydroxide = 0.100 × 0.0250

= 0.00250 mol

Step 2: Find the amount of hydrochloric acid in moles

The balanced equation is: NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l)

So the mole ratio NaOH:HCl is 1:1

Therefore 0.00250 mol of NaOH reacts with 0.00250 mol of HCl

Step 3: Calculate the concentration of hydrochloric acid in mol/dm3

Volume of hydrochloric acid = 20.00 ÷ 1000 = 0.0200 dm3

Concentration in mol/dm3 =

Concentration in mol/dm3 =

= 0.125 mol/dm3

Step 4: Calculate the concentration of hydrochloric acid in g/dm3

Relative formula mass of HCl = 1 + 35.5 = 36.5

Mass = relative formula mass × amount

Mass of HCl = 36.5 × 0.125

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8 0
3 years ago
Calculate the percentage of each element in acetic acid, hc2h3o2, and glucose, c6h12o6.
My name is Ann [436]
<em>Acetic acid, HC2H3O2</em>

First, calculate for the molar mass of acetic acid as shown below.
    M = 1 + 2(12) + 3(1) + 2(16) = 60 g

Then, calculating for the percentages of each element.
<em> Hydrogen:</em>
    P1 = ((4)(1)/60)(100%) = <em>6.67%</em>

<em> Carbon:</em>
   P2 = ((2)(12)/60)(100%) = <em>40%</em>

<em>Oxygen</em>
  P3 =((2)(16) / 60)(100%) = <em>53.33%</em>

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The molar mass of glucose is as calculated below,
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The percentages of the elements are as follow,
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<em>Carbon:</em>
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<em>Oxygen:</em>
  P3 = ((6)(16) / 180)(100%) = <em>53.33%</em>

b. Since the empirical formula of the given substances are just the same and can be written as CH2O then, the percentages of each element composing them will just be equal. 
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Answer:

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Explanation:

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⇒ moles NH3 = (4.0 moles H2)×(2 mol NH3/3mol H2)

⇒ moles NH3 = 2.666 mol

⇒ moles NH3 ≅ 2.7 mol

5 0
3 years ago
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