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3 years ago

Which elements usually lose their valence electrons when they bond

2 answers:

7 0

Ionic bonding is when the valence electron is stripped from the molecule when bonding to equilibrate charge energy. The opposite is covalent bonding, where electrons are not lost but shared.

Ionic bonding is seen when metals interact with non metals and other metals

the element that loses the valence electron is the one that is more positively charged. The element that gains the electron was more negatively charged.

masya89 [10]3 years ago

5 0

Metals, for example Cesium and Francium

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The EPA scientist measures the pH level in one area of a river to be lower than normal and writes that a pollutant must have bee

shutvik [7]

Its an example of inference.

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3 years ago

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Is each of these statements true? If not, explain why.(m) For most reactions, ΔH°rnx is lowered by a catalyst.

barxatty [35]

A catalyst reduces H°rnx in most reactions. The answer is false

<h3>Do catalysts reduce delta H?</h3>

By reducing the activation energy required for the reaction to occur, a catalyst just modifies the route used to go from reactants to products. However, because it doesn't alter the state of the products or reactants, delta H is unaffected.

A catalyst reduces a reaction's activation energy, enabling a chemical reaction to occur. The number of reactant particles with energy above the activation energy increases as the temperature of a reaction rises.

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1 year ago

Lauryl alcohol is a nonelectrolyte obtained from coconut oil and is used to make detergents. A solution of 6.80 g of lauryl alco

natka813 [3]

Answer:

The approximate molar mass of lauryl alcohol is 174.08 g/m

Explanation:

An excersise to apply the colligative property of Freezing-point depression.

This is the formula: ΔT = Kf . m

First of all, think the T° of fusion of benzene → 5.5°C

ΔT = T° pure solvent - T° fusion solution

Kf for benzene: 5.12 °C/m

5.5°C - 4.5°C = 5.12 °C /m . m

1°C / 5.12 m /°C = m

0.195 m = molality

This moles of lauryl alcohol, solute, are in 1 kg of benzene, solvent.

I have to find out in 0.2 kg.

1 kg sv ____ 0.195 moles solute

0.2 kg sv ____ (0.195 . 0.2)/1 = 0.039 moles solute

The mass for these moles is 6.80 g, so if I want to know the molar mass, I have to divide mass / moles

6.80 g/ 0.039 moles = 174.08 g/m

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3 years ago

25 POINTS!

ryzh [129]

Answer: The Answer is B. Energy can not be created nor destroyed.

Explanation:

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3 years ago

An alkyne with the molecular formula C5H8 was reduced with H2 and Lindlar's catalyst. Hydroboration-oxidation of the resulting a

irinina [24]

Since the addition of the H2O in the last step of hydroboration is anti-Markovnikov, the starting material is 1-pentyne.

The addition of H2 to C5H8 yields an alkene when a Lindlar catalyst is used. Recall that the Lindlar catalysts poisons the process so that the addition do not go on to produce an alkane.

When hydroboration is carried out on the alkene, we are told that a primary alcohol was obtained. We must note that in the last step of hydroboration, water is added in an anti- Markovnikov manner to yield the primary alcohol. Hence, the starting material must be 1-pentyne as shown in the image attached.

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3 years ago