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3 years ago

1. A particle has a mass of 10 kg and a velocity of 5 m/s. What is the momentum of the particle?

Physics

1 answer:

Aleksandr [31]3 years ago

8 0

✰ Concept :-

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We know that momentum is the product of mass and velocity. Thus, by the following definition, we get :-

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$\qquad \maltese \: \underline{ \boxed{ \purple{ \sf Momentum = Mass \times Velocity }}} \: \star$

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✰ Given Information :-

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A particle has mass 10 kg
Moving with velocity 5 m/s

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✰ To Find :-

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The momentum of the particle

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✰ Solution :-

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Using the formula from the concept section, we get :-

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$\sf \longrightarrow Momentum =10 \: kg \times 5 \: {m}^{ - 1} ~~~ \\ \\ \\\sf \longrightarrow Momentum = {50~kg \: ms}^{ - 1} \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \\ \sf \longrightarrow \underline{ \boxed{ \frak{ \orange{Momentum = {50 ~kg\: ms}^{ - 1} }}}} \: \star \: \: \: \: \: \: \\ \\$

Thus, the momentum of the particle is 50 kg m/s.

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$\underline{ \rule{230pt}{2pt}} \\ \\$

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3 years ago

A 5.30kg block hangs from a spring with a spring constant 1700 N/m. The block is pulled down 4.50cm from the equilibrium positio

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To solve this problem it is necessary to apply the concepts related to the frequency in a spring, the conservation of energy and the total mechanical energy in the body (kinetic or potential as the case may be)

PART A) By definition the frequency in a spring is given by the equation

$f = \frac{1}{2\pi} \sqrt{\frac{k}{m}}$

Where,

m = mass

k = spring constant

Our values are,

k=1700N/m

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Replacing,

$f = \frac{1}{2\pi} \sqrt{\frac{1700}{5.3}}$

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$\frac{1}{2}kA^2 = \frac{1}{2}mv^2 + \frac{1}{2} kY^2$

Where,

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This expression is equivalent to,

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k=1700 N/m

V=1.70 m/s

y=0.045m

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Replacing we have,

$1700*A^2=5.3*1.7^2 +1700*(0.045)^2$

Solving for A,

$A^2 = \frac{5.3*1.7^2 +1700*(0.045)^2}{1700}$

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4 years ago

Read 2 more answers

Please help me!

sergeinik [125]

C. The Densities are equal.

<h3>What is density?</h3>

Density is mass per unit volume or mass of a unit volume of a material substance.

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m2, V2 and D2 = mass, volume and density respectively of ball D

According to the Question ,

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Therefore,

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Hence, D1 = D2

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3 years ago