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makvit [3.9K]
2 years ago
13

1. A particle has a mass of 10 kg and a velocity of 5 m/s. What is the momentum of the particle?

Physics
1 answer:
Aleksandr [31]2 years ago
8 0

✰ <u>Concept</u><u> </u><u>:</u><u>-</u>

⠀

We know that momentum is the product of mass and velocity. Thus, by the following definition, we get :-

⠀

\qquad \maltese \:  \underline{  \boxed{ \purple{ \sf Momentum = Mass \times Velocity }}} \:  \star

⠀

✰ <u>Given</u><u> </u><u>Information</u><u> </u><u>:</u><u>-</u>

⠀

  • A particle has mass 10 kg
  • Moving with velocity 5 m/s

⠀

✰ <u>To Find</u><u> </u><u>:</u><u>-</u>

⠀

  • The momentum of the particle

⠀

✰ <u>Solution</u><u> </u><u>:</u><u>-</u>

⠀

Using the formula from the concept section, we get :-

⠀

\sf \longrightarrow Momentum =10 \: kg \times 5 \:  {m}^{ - 1} ~~~ \\  \\  \\\sf \longrightarrow Momentum = {50~kg \: ms}^{ - 1}   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \\  \\  \\   \sf \longrightarrow  \underline{ \boxed{ \frak{ \orange{Momentum = {50 ~kg\: ms}^{ - 1} }}}} \:  \star \:  \:  \:  \:  \:  \:  \\  \\

Thus, the momentum of the particle is 50 kg m/s.

⠀

\underline{ \rule{230pt}{2pt}} \\  \\

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I believe it would be Direction B

Explanation:

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Alexxx [7]

Answer:

soccer

Explanation:

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Hope this helps

3 0
3 years ago
What is the net charge of a metal ball if there are 21,749 extra electrons in it?
pickupchik [31]

Answer:

Q=3.47\times 10^{-15}\ C

Explanation:

Given that,

Number of extra electrons, n = 21749

We need to find the net charge on the metal ball. Let Q is the net charge.

We know that the charge on an electron is q=1.6\times 10^{-19}\ C

To find the net charge if there are n number of extra electrons is :

Q = n × q

Q=21749\times 1.6\times 10^{-19}\ C

Q=3.47\times 10^{-15}\ C

So, the net charge on the metal ball is 3.47\times 10^{-15}\ C. Hence, this is the required solution.

6 0
3 years ago
A falling object accelerates from -10.0 m/s to -30.0 m/s. how much time does it take?
Zepler [3.9K]

Answer:

2.04 s

Explanation:

v = at + v₀

(-30.0 m/s) = (-9.8 m/s²) t + (-10.0 m/s)

t = 2.04 s

8 0
3 years ago
Read 2 more answers
The near point of a person's eye is 71.4 cm. To see objects clearly at a distance of 24.0 cm, what should be the focal length an
yuradex [85]

Answer:

The focal length of the appropriate corrective lens is 35.71 cm.

The power of the appropriate corrective lens is 0.028 D.

Explanation:

The expression for the lens formula is as follows;

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}

Here, f is the focal length, u is the object distance and v is the image distance.

It is given in the problem that the given lens is corrective lens. Then, it will form an upright and virtual image at the near point of person's eye. The near point of a person's eye is 71.4 cm. To see objects clearly at a distance of 24.0 cm, the corrective lens is used.

Put v= -71.4 cm and u= 24.0 cm in the above expression.

\frac{1}{f}=\frac{1}{24}+\frac{1}{-71.4}

\frac{1}{f}=0.028

f= 35.71 cm

Therefore, the focal length of the corrective lens is 35.71 cm.

The expression for the power of the lens is as follows;

p=\frac{1}{f}

Here, p is the power of the lens.

Put f= 35.71 cm.

p=\frac{1}{35.71}

p=0.028 D

Therefore, the power of the corrective lens is 0.028 D.

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2 years ago
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