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Butoxors [25]
3 years ago
13

Question 6 (1 point)

Physics
1 answer:
jarptica [38.1K]3 years ago
8 0

Explanation:

decrease,then increase

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A vessel that contains a gas has two pressure gauges attached to it. One contains liquid mercury, and the other an oil such as d
castortr0y [4]

Answer:

Pressure of the gas = 12669 (Pa) and height of the oil is 1,24 meters

Explanation:

First, we can use the following sketch for an easy understanding, in the attached image we can see the two pressure gauges the one with mercury to the right and the other one with oil to left. We have all the information needed in the mercury pressure gauge, so we can determine the pressure inside the vessel because the fluid is a gas it will have the same pressure distributed inside the vessel (P1).

Since P1 = Pgas, we can use the same formula, but this time we need to determine the height of the column of oil in the pressure gauge.

The result is that the height of the oil column is higher than the height of the one that uses mercury, this is due to the higher density of mercury compared to oil.

Note: the information given in the units of the fluids is not correct because the density is always expressed in units of (mass /volume)

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3 years ago
Which conversion can take place in a transformer
Naddik [55]

Answer:

D. A lower Voltage into a higher

5 0
3 years ago
ffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffffff
mixer [17]

Answer:

fffffffffffffffffffffffffffff

5 0
3 years ago
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An object at rest will ______ unless acted upon by an unbalanced force.
zvonat [6]

Answer:

It's C because if you were trying to put it at rest that means you would put it on a Balanced surfest

4 0
2 years ago
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ly charged particles are held 24 x 103m apart and then released from rest. The initial acceleration of the first particle is obs
inessss [21]

Answer:

Part a)

m_2 = 4.9 \times 10^7 kg

Part b)

q_1 = q_2 = 5312.6 C

Explanation:

Part a)

As we know that both charge particles will exert equal and opposite force on each other

so here the force on both the charges will be equal in magnitude

so we will have

F = m_1a_1 = m_2a_2

here we have

6.3 \times 10^7(7) = m_2(9)

now we have

m_2 = 4.9 \times 10^7 kg

Part b)

Now for the force between two charges we can say

F = \frac{kq_1q_2}{r^2}

now we have

(6.3 \times 10^7)(7) = \frac{(9\times 10^9)q^2}{(24\times 10^3)^2}

now we have

q_1 = q_2 = 5312.6 C

3 0
3 years ago
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