At 100 km/hr, the car's kinetic energy is
KE = (1/2) (mass) (speed)²
KE = (1/2) (1575 kg) ( [100 km/hr] x [1000 m/km] x [1 hr/3600 sec] )²
KE = (787.5 kg) (27.78 m/s)²
KE = 607,639 Joules
In order to deliver this energy in 2.9 seconds, the engine must supply
(607,639 J / 2.9 sec) = 209,531 watts
<em>Power = 281 HP</em>
<span>Displacement is the difference between the initial position and the FINAL position of an object.
Hope this helps!</span>
14m/s
Explanation:
Given parameters:
Height of the ball = 10m
Unknown:
Velocity of fall or final velocity = ?
Solution:
We are going to use the appropriate equation of motion to solve this problem.
The object is falling with respect to gravity.
V² = U² + 2gH
where V is the final velocity
U is the initial velocity
g is the acceleration due to gravity 9.8m/s²
H is the height of fall
The initial velocity here is zero and
V² = 2 x 9.8 x 10 = 196
V = 14m/s
learn more:
Motion problems brainly.com/question/5248528
#learnwithBrainly
I believe the answer is C. Hope this helps!!
Complete Question
Q. Two go-carts, A and B, race each other around a 1.0km track. Go-cart A travels at a constant speed of 20m/s. Go-cart B accelerates uniformly from rest at a rate of 0.333m/s^2. Which go-cart wins the race and by how much time?
Answer:
Go-cart A is faster
Explanation:
From the question we are told that
The length of the track is 
The speed of A is 
The uniform acceleration of B is 
Generally the time taken by go-cart A is mathematically represented as
=> 
=> 
Generally from kinematic equation we can evaluate the time taken by go-cart B as

given that go-cart B starts from rest u = 0 m/s
So

=>
=>
Comparing
we see that
is smaller so go-cart A is faster