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Svet_ta [14]
2 years ago
11

An electric heater rated 500 W operates 24 hours/ day. what is the cost of energy to operate it for 20 days at Rs. 2.00 per kWh

?​
Physics
2 answers:
inessss [21]2 years ago
6 0

<u>Answer :</u>

  • Cost of energy = Rs. 480

<u>Step-by-step explanation :</u>

Given that, An electric heater rated 500 W operates 24 hours/ day.

We need to find the cost of energy to operate it for 20 days at Rs. 2.00 per kWh.

Power = 500 W = 500/1000 = 0.5 kW

Enegry consumed in one day :-

→ Enegry = P × t

→ Enegry = (0.5 kW) × 24 h

→ Enegry = 12 kWh

Ennegry consumed in 20 days will be:

→ Enegry = 12 × 20

→ Energy = 240 kWh

So,

→ Cost of enegry = 240 × 2

→ Cost of enegry = Rs. 480

Hence,

  • <u>Cost of energy to operate it for 20 days at Rs. 2.00 per kWh is Rs. 480</u>
Rina8888 [55]2 years ago
4 0

Answer:

Rs. 480.00

Explanation:

1kW = 1000W

therefore 500W = 0.5kW

20 × 24hrs = 480hrs in total.

0.5kW × 480hrs = 240kWh

if rs. 2 for 1kWh

then, 240kWh × 2 = Rs. 480.

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The kayaker has velocity vector

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<em>v</em> + <em>w</em> ≈ (2.65 m/s) <em>i</em> + (0.884 m/s) <em>j</em>

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5 0
3 years ago
A wire of Nichrome (a nickel– chromium– iron alloy commonly used in heating elements) is 1.0 m long and 1.0 mm² in cross-se
Lyrx [107]

Answer:

The conductivity of Nichrome is 2\times 10^6\ S/m.

Explanation:

Given:

Potential difference (V) = 2.0 V

Current flowing (I) = 4.0 A

Length of wire (L) = 1.0 m

Area of cross section of wire (A) = 1.0 mm² = 1 × 10⁻⁶ m² [1 mm² = 10⁻⁶ m²]

We know, from Ohm's law, that the ratio of voltage and current is always a constant and equal to the resistance of the resistor. Therefore, the resistance of the nichrome wire is given as:

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Now, conductivity of a material is the reciprocal of its resistivity. Therefore, the conductivity of Nichrome is given as:

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