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pickupchik [31]
2 years ago
11

Please can i have help answering the question in the picture

Mathematics
2 answers:
s2008m [1.1K]2 years ago
5 0
The answer is gonna be x+3/x-2

Flauer [41]2 years ago
3 0

Hey there!

Answer: \Rightarrow \sf{\frac{x+3}{x -2}}

\rightarrow \sf{ \frac{ {x}^{2} + 5x + 6 }{ {x}^{2} - 4 } }

\rightarrow{ \rm{factorise} \sf{ \frac{ {x}^{2} + 5x + 6 }{ {x}^{2} - 4 } } =  \frac{(x + 2)(x + 3)}{ {x}^{2}  - 4}  =  \frac{(x + 2)(x + 3)}{(x + 2)(x - 2)}  =  \Rightarrow \sf{\frac{x+3}{x -2}}}

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Which multiplication expression is equivalent to
oee [108]

Answer:

1

Step-by-step explanation:

Correct question:  2x2 - 5x - 3 / 4x2 + 12x + 5 divided by 3x2 - 11x + 6 / 6x2 + 11x - 10.

As given: \frac{(2x^{2}-5x-3) }{(4x^{2}+12x+5 )} \div \frac{(3x^{2} -11x+6)}{(6x^{2}+11x-10) }

Solving it by using quadratic equation.

= \frac{(2x^{2}-6x+1x-3) }{(4x^{2}+10x+2x+5) } \div \frac{(3x^{2}-9x-2x+6 }{(6x^{2}+15x-4x-10) }

= \frac{(2x+1) (x-3)}{(2x+1) (2x+5)} \div \frac{(3x-2) (x-3)}{(2x+5) (3x-2)}

To divide fraction take the reciprocal of divisor and multiply the dividend.

= \frac{(2x+1) (x-3)}{(2x+1) (2x+5)} \times \frac{(2x+5) (3x-2)}{(3x-2) (x-3)}

We solve it to get 1 as it cancel fraction on both side.

Answer is 1.

5 0
3 years ago
Read 2 more answers
I need help, please im stuck on this problem
Mazyrski [523]

Answer:

<em>0</em><em>.</em><em>0</em><em>3</em><em>5</em><em> </em><em>gram</em><em>.</em><em>.</em><em>.</em><em>.</em>

Step-by-step explanation:

.........

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2 years ago
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Does anyone know this answer​
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0 is the answer of questions

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Tim goes on a car journey
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Answer:

vroom vroom he keeps driving

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the length of a rectangle is 27cm less than five times its width. Its area is 56 square cm. Find the dimensions of the rectangle
Pavlova-9 [17]
I hope this helps you

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4 years ago
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