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2 years ago

Jaydon has eaten 3.6% his 45 ounce block of chocolate

Mathematics

1 answer:

elena-s [515]2 years ago

4 0

Answer:

The answer is 1.62 ounce

Step-by-step explanation:

<h3><u>Given</u>;</h3>

Jaydon has eaten 3.6% of his 45 ounce block of chocolate fudge.

How many ounces of fudge has he eaten?

Now,

3.6% of his 45 ounce

45 × 3.6 ÷ 100

162 ÷ 100 = 1.62

Thus, Jaydon has eaten 1.62 ounce block of chocolate fudge.

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marishachu [46]

Answer:

A. -4-3x>7

Step-by-step explanation:

-4-3(-5)>7

-4-(-15)>7

11>7

3 0

3 years ago

Write a whole number and a fraction greater than 1 to name the part filled.Think : 1 container = 1

kykrilka [37]

Alright.....so..... well the
Whole Number: 4 id greater than one
Fraction: 4/1

I am not a 100% sure but try another source also<span />

8 0

3 years ago

Read 2 more answers

What are the possible values of x in 8x2 + 4x = -1?

Westkost [7]

Answer:

The possible values of x are:

x= $\frac{-1+\sqrt{3}}{4} \,\,or\,\, x= 0.18$

and

x= $\frac{-1-\sqrt{3}}{4} \,\, or \,\, x= -0.68$

Step-by-step explanation:

$8x^2+4x+1=0$

Using Quadratic formula to solve this equation:

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\a = 8 \,\, b = 4\,\, c = -1\\Putting \,\, values \,\, in \,\, the\,\, equation\\x= \frac{-4\pm\sqrt{(4)^2-4(8)(-1)}}{2(8)}\\x= \frac{-4\pm\sqrt{16+32}}{16}\\x= \frac{-4\pm\sqrt{48}}{16}\\x= \frac{-4+ \sqrt{48}}{16} \,\, and \,\, x= \frac{-4- \sqrt{48}}{16}\\x= \frac{-1+ \sqrt{3}}{4} \,\, and \,\, x= \frac{-1- \sqrt{3}}{4}$

The possible values of x are:

x= $\frac{-1+\sqrt{3}}{4} \,\,or\,\, x= 0.18$

and

x= $\frac{-1-\sqrt{3}}{4} \,\, or \,\, x= -0.68$

4 0

3 years ago

Hola, estoy empezando a ver trigonometria queria ver si me pueden ayudar con este problema: Un extraterrestre diminuto pero horr

Kryger [21]

Answer:

El agente debe disparar a un ángulo aproximado de 87.7° con respecto a la horizontal.

Step-by-step explanation:

Sea E la localización del extraterrestre, O, el del hombre de negro, y B, el de la base del edificio. A partir de la información disponible, construimos el diagrama geométrico que indica la presencia de un triángulo rectángulo, el cual puede consultarse en la imagen adjunta.

Podemos determinar el ángulo de disparo mediante la siguiente relación trigonométrica inversa:

$A = \tan^{-1} \frac{443\,m}{18\,m}$