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Roman55 [17]
3 years ago
9

What is the range of the function?

Mathematics
1 answer:
levacccp [35]3 years ago
7 0

Answer:

e equels MC squared

Step-by-step explanation:

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A triangular prism is 13 meters long and has a triangular face with a base of 12.6 meters and a height of 16.6 meters. What is t
kolbaska11 [484]

Answer:

1359.54m^3

Step-by-step explanation:

The formula for the volume of a triangular prism is:

1/2(b \times l )\times h

<em>b= base </em>

<em>l = length</em>

<em>h</em><em>= </em><em>height</em>

Step 1: Plug the numbers into the formula

1/2(12.6*13)*16.6

Step 2: Simplify

163.8*16.6

1359.54

Step 3: Add units

The units used in the question were in meters, so the answer is also in meters.

Volume is always cubed, so it would be to the third power...1359.54m^3

If this answer helped you, I would greatly appreciate if you gave me brainliest :D.

5 0
2 years ago
Y + 3 = –y + 9<br><br> y = 1<br> y = 3<br> y = 6<br> y = 9
AVprozaik [17]

Answer:

y=3

Step-by-step explanation:

y + 3 = - y + 9

y + y = 9 - 3

2y = 6

y = 6/2

y =3

8 0
3 years ago
A ladder, 14 feet long, is leaning against
PolarNik [594]

Answer:

12.12ft

Step-by-step explanation:

14² = 7² + x²

x² = 14² - 7²

x² = 196 - 49

x² = 147

x = √147

x = 12.12ft

6 0
3 years ago
Read 2 more answers
And the last question is:
Leya [2.2K]
It should be " b " That should be right but u may want to wait for others to respond to this to make sure
6 0
3 years ago
Read 2 more answers
Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2
Mkey [24]

For this case, we have to:

By definition, we know:

The domain of f (x) = \sqrt [3] {x} is given by all real numbers.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. In the same way, its domain will be given by the real numbers, independently of the sign of the term inside the root. Thus, it will always be defined.

So, we have:

y = \sqrt [3] {x-2} withx = 0: y = \sqrt [3] {- 2} is defined.

y = \sqrt [3] {x+2}with x = 0:\ y = \sqrt [3] {2} is also defined.

f (x) = \sqrt {x}has a domain from 0 to ∞.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

y = \sqrt {x-2} is not defined, the term inside the root is negative whenx = 0.

While y = \sqrt {x+2} if it is defined for x = 0.

Answer:

y = \sqrt {x-2}

Option b

6 0
3 years ago
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