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LekaFEV [45]
2 years ago
9

What is the percent of oxygen by mass in C2H402

Chemistry
1 answer:
Rom4ik [11]2 years ago
6 0

Answer:

53.3 %.

Explanation: C2H4O2. = 2 * 12.011 + 4 * 1.008 + 2 * 15.999. = 60.052.

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Jen makes a Venn diagram to compare active transport and passive transport.
Oksanka [162]

Answer:

moves molecules

Explanation:

I did this one yesterday! Active transport moves low to high concentration and passive does the opposite so C and D are not an option. Active transport requires energy and Passive Transport does not so it has to be A.!

6 0
3 years ago
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Help with number 3 plz help due tomorrow!!!!!!!!!!
IceJOKER [234]

Answer:

which one?

Explanation:

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4 0
3 years ago
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Along each row of the periodic table,
Naddik [55]

the answer to your question is A

7 0
3 years ago
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I am not Neon, but I am a noble gas with a mass of less than 30.
Setler [38]

I believe your answer would be helium friend :)

8 0
3 years ago
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One of the radioactive isotopes used in medical treatment or analysis is chromium-51. The half-life of chromium-51 is 28 days. H
Goryan [66]

Answer : The time required for decay is, 84 days.

Explanation :

Half-life of chromium-51 = 28 days

First we have to calculate the rate constant, we use the formula :

k=\frac{0.693}{t_{1/2}}

k=\frac{0.693}{28\text{ days}}

k=0.0248\text{ days}^{-1}

Now we have to calculate the time required for decay.

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = time taken by sample = ?

a = let initial activity of the sample = 100

a - x = amount left after decay process  = 12.5

Now put all the given values in above equation, we get

t=\frac{2.303}{0.0248}\log\frac{100}{12.5}

t=83.9\text{ days}\approx 84\text{ days}

Therefore, the time required for decay is, 84 days.

7 0
3 years ago
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