Answer:Hence, in 8g of Oxygen molecules, there are 3. 011 x 10²³ Oxygen atoms. In this way, how many moles are in 16 grams of oxygen? In other words, 1 mole of oxygen would contain molecules
Explanation:
1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p5
Answer:
There was a change in temperature on the surface you were walking on. It is possible that "you" were walking on cool, wet sand and when your parents said it was time to leave, you ran barefoot towards the parking lot (away from the sand) and got a burning coal sensation on your feet.
Explanation:
Answer:
C) 1 x 10-10 M
Explanation:
To solve this question we must use the equation:
Kw = [H+] [OH-]
<em>Where Kw is the equilibrium dissociation of water = 1x10-14</em>
<em>[H+] is the molar concentration of hydronium ion = 1x10-4M</em>
<em>[OH-] is the molar concentration of hydroxyl ion</em>
<em />
Replacing:
1x10-14= 1x10-4 [OH-]
<em>[OH-] = 1x10-14 / 1x10-4M</em>
<em>[OH-] = 1x10-10 M</em>
Right option is:
<h3>C) 1 x 10-10 M
</h3>
Answer:
0.0055 mol of N2O5 will remay after 7 min.
Explanation:
The reaction follows a first-order.
Let the concentration of N2O5 after 7 min be y
Rate = Ky = change in concentration of N2O5/time
K is rate constant = 6.82×10^-3 s^-1
Initial concentration of N2O5 = number of moles/volume = 2.1×10^-2/1.8 = 0.0117 M
Change in concentration = 0.0117 - y
Time = 7 min = 7×60 = 420 s
6.82×10^-3y = 0.0117 - y/420
0.0117 - y = 420×6.82×10^-3y
0.0117 - y = 2.8644y
0.0117 = 2.8644y + y
0.0117 = 3.8644y
y = 0.0117/3.8644 = 0.00303 M
Number of moles of N2O5 left = y × volume = 0.00303 × 1.8 = 0.0055 mol (to 2 significant digits)
