Answer:
8.912x10^-18
Explanation:
-dn/dt = pANa/2piMRT
100 g = initial copper
Number of moles = 100/63.546
= 1.5736
Mass of copper left = 100-10.0168
= 89.9832
Moles = 89.9832/63.546
= 1.4160
dn = 1.4160-1.5736
= -0.1576
dt = 2 hrs
A = 3.23mm² = 3.23x10^-6
M = 63.546
T = 0.0821
T = 1508k
Na = 6.023x10²³
When we insert all these into the formula above
We get
P = 8.912x10^-18atm
A cation is a positive ion. That means it lost an electron.
Answer:
9.8 × 10^21
Explanation:
Equation of the reaction;
Cd(s) + Ni^2+(aq) ----> Cd^2+(aq) + Ni(s)
E°cell= E°cathode - E°anode
E°cathode= -0.25 V
E°anode = -0.40 V
E°cell= -0.25 - (-0.40)
E°cell = 0.65 V
∆G= -nFE°cell
∆G= -(2 × 96500 × 0.65)
∆G = -125450 J
From;
∆G= -RTlnK
lnK = ∆G/-RT
K= e^∆G/-RT
K= e^-[-(125450/8.314 × 298)]
K= 9.78 × 10^21
Answer:
(a) Three translational degrees of freedom, 2 rotational degrees. 5 total
Cv = 5/2 R; Cp = 7/2 R
(b) and (c) 6 total degrees of freedom ( 3 translational, 3 rotational)
Cv = 3 R ; Cp = 4R
Explanation:
(a) O₂
Oxygen being a diatomic molecule has three translational degrees of freedom and two rotational degrees of freedom since it can move in the three axis and can rotate around two.
(b) H₂O
This is a polyatomic molecule and it has three translational and three rotational degrees of freedom.
(c) Same as water it has three translational degrees of freedom and three rotational degrees of freedom
To calculate the heat capacities we have to make use of the equipartition theorem which tell us that for each degree of freedom imparts 1/2 R to the heat capacity at constant volume.
(a)
5 total degrees of freedom ⇒ Cv = 5/2 R
Cp ( heat capacity at constant pressure) is determined from the relation
Cp - Cv = R
Cp = 7/2 R for O2 molecule
(b) and (c)
Total degrees of freedom 6
Cv = 3 R
Cp = 4 R
Here we are ignoring any contribution of the vibrational modes to the contribution of the heat capacities
