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vesna_86 [32]
3 years ago
10

A pile of marbles weigh 394.80 g. 10 marbles weigh37.60 g. How many marbles are in the pile?​

Chemistry
1 answer:
Valentin [98]3 years ago
4 0

Answer:

10=37.60g

???=394.80g

<u>10</u><u>×</u><u>394</u><u>.</u><u>80</u>

37.60

=105marbled

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The method that can be used to separate the mixture is chromatography.

<h3>What is chromatography?</h3>

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To obtain the colors used, two solvents are mixed and the sample ink is dissolved in the solvents then spotted on a thin layer and put into a TLC chamber then the chromatogram is allowed to develop.

The various components of the pigment will appear on the chromatogram and can be identified using spectrophotometry. The Rf values of each component can also be used to identify it.'

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Neon is an inner gas because it’s outer ____ is full of electrons.
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Answer:

Neon is an inner gas because it’s outer <u>__shell__</u> is full of electrons.

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How many mL of .450 M HCL is needed to neutralize 30mL of .150 M Ba(OH)2
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Which quantity is equivalent to the product of the absolute index of refraction of water and the speed of light in water?
givi [52]

The quantity which is equivalent to the product of the absolute index of refraction of water and the speed of light in water system is the speed of light in vacuum.

<h3>What is the speed of light?</h3>

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v=\dfrac{c}{n}

Here, (n) is the index of reaction and (c) is the speed of light in the vacuum. The speed of light in the vacuum is almost equal to the 3.0×10⁸ m/s.

Now the quantity which is equivalent to the product of the absolute index of refraction of water and the speed of light in water has to be find out.

The above formula can be written as,

v=\dfrac{c}{n}\\vn=c\\c=vn

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3 0
2 years ago
The equilibrium constant Kc for the decomposition of phosgene, COCl2, is 4.63x10^-3 at 527 C. Calculate the equilibrium partial
Studentka2010 [4]

<u>Answer:</u> The partial pressure of the CO,Cl_2\text{ and }COCl_2 are 0.352 atm, 0.352 atm and 0.408 atm respectively.

<u>Explanation:</u>

We are given:

K_c=4.63\times 10^{-3}

p_{COCl_2}=0.760atm

Relation of K_p with K_c is given by the formula:

K_p=K_c(RT)^{\Delta ng}

Where,

K_p = equilibrium constant in terms of partial pressure = ?

K_c = equilibrium constant in terms of concentration = 4.63\times 10^{-3}

R = Gas constant = 0.0821\text{ L atm }mol^{-1}K^{-1}

T = temperature = 527^oC=527+273=800K

\Delta ng = change in number of moles of gas particles = n_{products}-n_{reactants}=2-1=1

Putting values in above equation, we get:

K_p=4.63\times 10^{-3}\times (0.0821\times 800)^{1}\\\\K_p=0.304

The chemical reaction for the decomposition of phosgene follows the equation:

                   COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)

At t = 0          0.760            0     0  

At t=t_{eq}      0.760-x          x      x

The expression for K_p for the given reaction follows:

K_p=\frac{p_{CO}\times p_{Cl_2}}{p_{COCl_2}}

We are given:

K_p=0.304\\p_{COCl_2}=0.760-x\\p_{CO}=x\\p_{Cl_2}=x

Putting values in above equation, we get:

0.304=\frac{x\times x}{0.760-x}\\\\x=0.352,-0.656

Negative value of 'x' is neglected because partial pressure cannot be negative.

So, the partial pressure for the components at equilibrium are:

p_{COCl_2}=0.760-0.352=0.408atm\\\\p_{CO}=0.352atm\\\\p_{Cl_2}=0.352atm

Hence, the partial pressure of the CO,Cl_2\text{ and }COCl_2 are 0.352 atm, 0.352 atm and 0.408 atm respectively.

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3 years ago
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