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3 years ago

5>x/5 Show all work in steps

Mathematics

2 answers:

Vlad1618 [11]3 years ago

8 0

Answer:

25 > x

Step-by-step explanation:

$5 > \frac{x}{5}$

To find the value of x, you have to multiply both sides by 5.

$5*5 > \frac{x}{5}* 5$

$25 > \frac{5x}{5}$

$25 > x$

Mademuasel [1]3 years ago

7 0

Answer:

$\boxed{\sf{x < 25}}$

Step-by-step explanation:

To find the value of x, isolate it on one side of the equation.

First, you have to switch sides.

→ x/5<5

Then, you multiply by 5 from both sides.

→ 5x/5<5*5

Solve.

Multiply the numbers from left to right.

→ 5*5=25

→ x<25

Therefore, the solution is x<25, which is our answer.

I hope this helps you! Let me know if my answer is wrong or not.

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Solve for x in a right triangle (show work)

Semmy [17]

Answer:

x = 89. 98⁰

Step-by-step explanation:

tan(x) = 29/ 14

x = tan-¹ (29/14)

x = 89. 98⁰

3 0

2 years ago

(3x-5)/(x-5)>=0 How do I get the answers for this problem?

Diano4ka-milaya [45]

$\frac{3x-5}{x-5}$ > 0

First, note that x is undefined at 5. / x ≠ 5
Second, replace the inequality sign with an equal sign so that we can solve it like a normal equation. / Your problem should look like: $\frac{3x-5}{x-5}$ = 0
Third, multiply both sides by x - 5. / Your problem should look like: 3x - 5 = 0
Forth, add 5 to both sides. / Your problem should look like: 3x = 5
Fifth, divide both sides by 3. / Your problem should look like: x = $\frac{5}{3}$
Sixth, from the values of x above, we have these 3 intervals to test:
x < $\frac{5}{3}$
$\frac{5}{3}$ < x < 5
x > 5
Seventh, pick a test point for each interval.

1. For the interval x < $\frac{5}{3}$ :
Let's pick x - 0. Then, $\frac{3x0-5}{0-5}$ > 0
After simplifying, we get 1 > 0 which is true.
Keep this interval.

2. For the interval $\frac{5}{3}$ < x < 5:
Let's pick x = 2. Then, $\frac{3x2-5}{2-5}$ > 0
After simplifying, we get -0.3333 > 0, which is false.
Drop this interval.

3. For the interval x > 5:
Let's pick x = 6. Then, $\frac{3x6-5}{6-5}$ > 0
After simplifying, we get 13 > 0, which is ture.
Keep this interval.
Eighth, therefore, x < $\frac{5}{3}$ and x > 5

Answer: x < $\frac{5}{3}$ and x > 5

3 0

4 years ago

According to the Rational Root Theorem, what are all the potential rational roots of f(x) = 15x11 – 6x8 + x3 – 4x + 3?

scoundrel [369]

we have

$f(x) = 15x^{11} -6x^{8} + x^{3} - 4x + 3$