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bezimeni [28]
2 years ago
6

Plsplsplsplspslpslpslpslpslpslpspslsplsplsplsplsp helphelphelphelp mememememem

Mathematics
1 answer:
Sholpan [36]2 years ago
3 0
<h2>Dude Calm down you can just look it up</h2>

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A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2
Yuliya22 [10]

A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2 and 5.1.

Answer: The correct option is B) about 34%

Proof:

We have to find P(4.2

To find P(4.2, we need to use z score formula:

When x = 4.2, we have:

z = \frac{x-\mu}{\sigma}

          =\frac{4.2-5.1}{0.9}=\frac{-0.9}{0.9}=-1

When x = 5.1, we have:

z = \frac{x-\mu}{\sigma}

          =\frac{5.1-5.1}{0.9}=0

Therefore, we have to find P(-1

Using the standard normal table, we have:

P(-1= P(z

                               =0.50-0.1587

                               =0.3413 or 34.13%

                               = 34% approximately

Therefore, the percent of data between 4.2 and 5.1 is about 34%

7 0
3 years ago
Mr. Crawford’s 4th-Period math class I ready question
drek231 [11]

Answer:

yes

Step-by-step explanation:

yes

6 0
3 years ago
Which number is the common difference of the sequence -92,-74,-54,-38,-20?
Mkey [24]
The common difference if there is one is the constant difference that occurs between any term and the term before it.... in this case:

There is no common difference, 

dx=18,20,16,18  the difference or velocity is not constant...

d2x=2, -4,2  the acceleration is not constant...

d3x=-6,6  the thrust is not constant  

Now we might be tempted to say that:

d4x=12 and say that that is constant and we COULD make a quartic equation fit all the data points, but without further data points in the sequence there is no mathematical proof that the quartic equation would produce accurate data points outside of the range given...

And solving a system of five equations for five unknowns is tedious for such a problem...a^4+bx^3+cx^2+dx+e=y

8 0
3 years ago
Read 2 more answers
I need to find the distance between these two points:
FromTheMoon [43]
I hope this helps you

8 0
3 years ago
I am greater than 310. My number has 0 ones.The digits in my hundreds and tens places are the same
mixas84 [53]

Step-by-step explanation:

Numbers: 330, 440, 550, 660 and so on all the way to 990

7 0
2 years ago
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