Question

A glass container was initially charged with 1.95 moles of a gas sample at 3.75 atm and 21.7 °C. Some of the gas was released as the temperature was increased to 28.1 °C, so the final pressure in the container was reduced to 0.998 atm. What quantity in moles of the gas sample are present at the end?

Answer 1

Answer:

45830.4 moles

Explanation:

Ideal gas law is the hypothetical equation in which the pressure, volume, and temperature of the gas are directly related. It can be denoted as:

PV = nRT

The ideal gas law is:

PV = nRT

where,

P = Pressure

V = Volume

R = Gas constant

T =Temperature

n = moles

Given:

Moles in container = 1.95

Temperture = 294.85 K

Pressure = 3.75 atm

Volume =?

Substituting the values:

V = nRT/P

V = 1.95 × 0.082 × 294 / 3.75

Volume = 12.5 L

Now, the condition when changed, such that temperature is 301.25 K, pressure is 0.998 atm, and Volume is 12.5 L, then moles will be equal to:

PV/RT = n

0.998 × 12.5 / 0.082 × 301.25 = n

n = 45830.4 moles

Therefore, 0.521 moles is still present in the container.

To know more about ideal gas law, refer to the following link:

brainly.com/question/12124605