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Serjik [45]
3 years ago
6

An object moves 2.5 m. This is an example of a _______.

Physics
2 answers:
makvit [3.9K]3 years ago
7 0

The correct answer is A. Distance

Hope this helps

Stells [14]3 years ago
6 0

An object moves 2.5 m. This is an example of a Distance

Answer: Option A

<u>Explanation:</u>

Direction denotes whether positive or negative or the left and right direction of an object. Speed and velocity are used to represent the distance travelled by the object with respect to the time taken by the object to travel.

Distance and displacement denotes the position the object has travelled from its previous location. Hence Option A is correct and B, C, D are irrelevant.

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Electric field lines show the strength and _____ of an electric field.
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3 years ago
A block of ice(m = 14.0 kg) with an attached rope is at rest on a frictionless surface. You pull the block with a horizontal for
nadezda [96]

Answer:

a) The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) The final speed of the block of ice is 9.8 meters per second.

Explanation:

a) We need to calculate the weight, normal force from the ground to the block and the pull force. By 3rd Newton's Law we know that normal force is the reaction of the weight of the block of ice on a horizontal.

The weight of the block (W), measured in newtons, is:

W = m\cdot g (1)

Where:

m - Mass of the block of ice, measured in kilograms.

g  - Gravitational acceleration, measured in meters per square second.

If we know that m = 14\,kg and g = 9.807\,\frac{m}{s^{2}}, the magnitudes of the weight and normal force of the block of ice are, respectively:

N = W = (14\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)

N = W = 137.298\,N

And the pull force is:

F_{pull} = 98\,N

The weight and the normal force of the block has a magnitude of 137.298 newtons and the pull force exerted on the block has a magnitude of 98 newtons.

b) Since the block of ice is on a frictionless surface and pull force is parallel to the direction of motion and uniform in time, we can apply the Impact Theorem, which states that:

m\cdot v_{o} +\Sigma F \cdot \Delta t = m\cdot v_{f} (2)

Where:

v_{o}, v_{f} - Initial and final speeds of the block, measured in meters per second.

\Sigma F - Horizontal net force, measured in newtons.

\Delta t - Impact time, measured in seconds.

Now we clear the final speed in (2):

v_{f} = v_{o}+\frac{\Sigma F\cdot \Delta t}{m}

If we know that v_{o} = 0\,\frac{m}{s}, m = 14\,kg, \Sigma F = 98\,N and \Delta t = 1.40\,s, then final speed of the ice block is:

v_{f} = 0\,\frac{m}{s}+\frac{(98\,N)\cdot (1.40\,s)}{14\,kg}

v_{f} = 9.8\,\frac{m}{s}

The final speed of the block of ice is 9.8 meters per second.

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2 years ago
A perfect bouncy ball would continue bouncing the same height forever. But in reality, the ball stops bouncing because energy is
galina1969 [7]

Answer:

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3 years ago
IMPORTANT!!! DUE IN 5 MINS I NEED HELP PLEASE
Ket [755]

Answer:

684.5 is the weight on mars and 1813 on earth

Explanation:

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