An object moves 2.5 m. This is an example of a _______.
2 answers:
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Answer:
Time, t = 5.355 seconds
Explanation:
Given the following data;
Distance = 100 m
Initial velocity = 16 m/s
Deceleration = 1 m/s²
To find the time, we would use the second equation of motion;
But since the ball is decelerating, it's acceleration would be negative.
S = ut + ½at²
Where;
S represents the displacement or height measured in meters.
u represents the initial velocity measured in meters per seconds.
t represents the time measured in seconds.
a represents acceleration measured in meters per seconds square.
Substituting into the equation, we have;
100 = 16t - 0.5t²
200 = 32t - t²
t² + 32t - 200 = 0
Solving the quadratic equation using the quadratic formula;
The quadratic equation formula is;
Substituting into the equation, we have;
x1 = 5.355
We do not need the negative value of x, so we proceed.
Therefore, time = 5.355 seconds