Consider two celestial objects with masses m1 and m2 with a separation distance between their centers r. If the first mass m1 we re to double and the second mass m2 were to triple, what would happen to the magnitude of the force of attraction
1 answer:
The new magnitude of the force of attraction will be 6 times the original force of attraction
<h3>How to determine the initial force </h3>
Mass 1 = m₁ Mass 2 = m₂ Gravitational constant = G Distance apart = r Initial force (F₁) = ?
F = Gm₁m₂ / r²
F₁ = Gm₁m₂ / r²
<h3>How to determine the new force </h3>
Mass 1 = 2m₁ Mass 2 = 3m₂ Gravitational constant = G Distance apart (r) = r New force (F₂) =?
F = Gm₁m₂ / r²
F₂ = G × 2m₁ × 3m₂ / r²
F₂ = 6Gm₁m₂ / r²
But
F₁ = Gm₁m₂ / r²
Therefore
F₂ = 6Gm₁m₂ / r²
F₂ = 6F₁
Thus, the new magnitude of the force of attraction will be 6 times the original force of attraction
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