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Taya2010 [7]
2 years ago
15

Consider two celestial objects with masses m1 and m2 with a separation distance between their centers r. If the first mass m1 we

re to double and the second mass m2 were to triple, what would happen to the magnitude of the force of attraction
Physics
1 answer:
Scilla [17]2 years ago
6 0

The new magnitude of the force of attraction will be 6 times the original force of attraction

<h3>How to determine the initial force </h3>
  • Mass 1 = m₁
  • Mass 2 = m₂
  • Gravitational constant = G
  • Distance apart = r
  • Initial force (F₁) = ?

F = Gm₁m₂ / r²

F₁ = Gm₁m₂ / r²

<h3>How to determine the new force </h3>
  • Mass 1 = 2m₁
  • Mass 2 = 3m₂
  • Gravitational constant = G
  • Distance apart (r) = r
  • New force (F₂) =?

F = Gm₁m₂ / r²

F₂ = G × 2m₁ × 3m₂ / r²

F₂ = 6Gm₁m₂ / r²

But

F₁ = Gm₁m₂ / r²

Therefore

F₂ = 6Gm₁m₂ / r²

F₂ = 6F₁

Thus, the new magnitude of the force of attraction will be 6 times the original force of attraction

Learn more about gravitational force:

brainly.com/question/21500344

#SPJ1

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What changes dead plants and animals into ammonia compounds?
lapo4ka [179]

Nitrogen fixing bacteria changes dead plants and animals into ammonia compounds.

<h2>What is nitrogen fixation?</h2>

Atmospheric nitrogen is converted into nitrogen oxides by the action of lightning, which helps its incorporation into the soil.

<h3>Characteristics of Nitrogen fixing bacteria</h3>

  • Nitrogen is fixed by these bacteria and other prokaryotes through various metabolic processes, which convert it into different usable compounds, such as ammonia (NH3) and ammonium ion (NH4+).

  • These microorganisms can be found in soil and water, or as plant symbionts.

Therefore, we can conclude that nitrogen fixing bacteria fix nitrogen from the air, that is, they originate soluble compounds by plants, such as ammonia.

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7 0
2 years ago
How will unbalanced forces affect the speed and direction of an object
azamat

Answer:

Explanation:

Unbalanced forces will result in the presence of acceleration. The formula

F net = ma

says that if there is a net force present and the object in question has a mass, then an acceleration is present. Now acceleration is constant in this situation because nowhere does it say the acceleration is changing. If acceleration is constant then the velocity is increasing at a steady pace (think linear function!).

The direction of the object depends on the direction that the net force is in. If the net force is to the left, then that object will accelerate to the left.

Hope this helps :)

3 0
3 years ago
You set your stationary bike on a high 80-N friction-like resistive force and cycle for 30 min at a speed of 8.0 m/s . Your body
stellarik [79]

A) The change in internal chemical energy is 1.15\cdot 10^7 J

B) The time needed is 1 minute

Explanation:

First of all, we start by calculating the power output of you and the bike, given by:

P=Fv

where

F = 80 N is the force that must be applied in order to overcome friction and travel at constant speed

v = 8.0 m/s is the velocity

Substituting,

P=(80)(8.0)=640 W

The energy output is related to the power by the equation

P=\frac{E}{t}

where:

P = 640 W is the power output

E is the energy output

t = 30 min \cdot 60 = 1800 s is the time elapsed

Solving for E,

E=Pt=(640)(1800)=1.15\cdot 10^6 J

Since the body is 10% efficient at converting chemical energy into mechanical work (which is the output energy), this means that the change in internal chemical energy is given by

\Delta E = \frac{E}{0.10}=\frac{1.15\cdot 10^6}{0.10}=1.15\cdot 10^7 J

B)

From the previous part, we found that in a time of

t = 30 min

the amount of internal chemical energy converted is

E=1.15\cdot 10^7 J

Here we want to find the time t' needed to convert an amount of chemical energy of

E'=3.8\cdot 10^5 J

So we can setup the following proportion:

\frac{t}{E}=\frac{t'}{E'}

And solving for t',

t'=\frac{E't}{E}=\frac{(3.8\cdot 10^5)(30)}{1.15\cdot 10^7}=1 min

Learn more about power and energy:

brainly.com/question/7956557

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3 0
2 years ago
For a movie stunt, an empty truck with a mass of 2000 kg goes 10 m/s and runs into a stopped car of mass 1000 kg. the truck then
babunello [35]

ANSWER

Both trucks will move together with speed v = 6.67 m/s

so correct answer will be

The speed of the combined vehicles is less than the initial speed of the truck.

EXPLANATION

As we know that there is no external force on the system of two trucks

So here momentum of the two trucks before collision and after collision will remain same

So here we will have

m_1v_{1i} + m_2v_{2i} = m_1v_{1f} + m_2v_{2f}

so here we will have

v_{1i} = 10 m/s

v_{2i} = 0

m_1 = 2000 kg

m_2 = 1000 kg

now we will have

2000\times 10 + 1000\times 0 = (2000 + 1000) v

v = \frac{20000}{3000} = 6.67 m/s

so correct answer will be

The speed of the combined vehicles is less than the initial speed of the truck.

3 0
2 years ago
Read 2 more answers
Determine the change in velocity of a car that start at rest and has a final velocity of 20 m/s north
romanna [79]
The change in velocity is 20 m/s to the north.
6 0
3 years ago
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