The instantenous velocity is just the slope of the graph at a certain instant. Since the graph is a straight line, its instantenous velocity is uniform through out. v = dx / dt = (40 - 10) / (50 - 0) = 0.6 m/s.
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C im pretty sure?.........
Answer:
1.034 m above the floor
Explanation:
The location of center of body for a compound body, when the weights are given is calculated as:
where,
is the center of gravity of the entire body
W = weight of the individual body
x = center of gravity of the individual body
Thus on substituting the values we get,
or
or
Hence, <u>the center of gravity of the entire body lies </u><u>1.034 m</u><u> </u><u>above the floor</u>
Newton taught us that Force = (mass) x (acceleration)
Force = (0.2) x (20) = <em>4 newtons</em> .
Something to think about: The ball can only accelerate while the club-face
is in contact with it. Once the ball leaves the club, it can't accelerate any more,
because the force against it is gone.
Answer: If a star's radial velocity is -50 km/s, the frequency of its light would appear to be higher than its true frequency. We usually say that the star's wavelength is blue shifted.
Explanation:
Radial velocity is defined as the velocity of how an object is seen by the axis of a circle.
Then, if the radial velocity is -50km/s, this means that the radius is decreasing, and then that the star is coming towards the viewer.
as the star is coming towards the viewer, we will see a shorter wavelength, which implies that the frequency would appear to be bigger as it really is.
and this is called a blue shift, because the blue light is the visible light with the biggest frequency, while the red light is the visible light with the smallest frequency, then we have:
If a star's radial velocity is -50 km/s, the frequency of its light would appear to be higher than its true frequency. We usually say that the star's wavelength is blue shifted.
