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Bas_tet [7]
3 years ago
10

Explain how atomic mass and molecular mass are determined

Physics
1 answer:
GaryK [48]3 years ago
4 0
Molecular mass may be calculated by taking the atomic mass of each element present and multiplying it by the number of atoms of that element in the molecular formula. Then, the number of atoms of each element is added together. This value may be reported as a decimal number or as 16.043 Da or 16.043 amu.
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A _ increases it decreases voltage in a power line
Levart [38]
A transformer increases and decreases voltage.
5 0
3 years ago
"A 78-year-old woman has a mean arterial pressure of 120 mm Hg and a heart rate of 60 beats/min. She has a stroke volume of 50 m
aivan3 [116]

Answer:

0.04 mm Hg / mL / min .

Explanation:

Arterial pressure = 120 mm Hg

right atrial pressure = 0 mm Hg

Drop in pressure due to peripheral resistance = 120 mm Hg

volume of cardiac output per minute = 3000 mL/min

total  peripheral resistance

= 120 / 3000 mm Hg / mL / min

= 0.04 mm Hg / mL / min .

8 0
3 years ago
A car’s bumper is designed to withstand a 4.0-km/h (1.1-m/s) collision with an immovable object without damage to the body of th
Alex Ar [27]

Answer:

 avriage force F = 2722.5 N

Explanation:

For this problem we can use Newton's second law, to calculate the average force and acceleration we can find it by kinematics.

      vf² = v₀² - 2 ax

The final carriage speed is zero (vf = 0)

      0 = v₀² - 2ax

      a = v₀² / 2x

      a = 1.1²/(2 0.200)

      a = 3.025 m / s²

      a = 3.0 m/s²

We calculate the average force

      F = ma

      F = 900 3,025

      F = 2722.5 N

3 0
3 years ago
An aluminum bar 600mm long, with diameter 40mm long has a hole drilled in the center of the bar.The hole is 30mm in diameter and
Svetradugi [14.3K]

Answer:

Total contraction on the Bar  = 1.22786 mm

Explanation:

Given that:

Total Length for aluminum bar = 600 mm  

Diameter for aluminum bar  = 40 mm

Hole diameter  = 30 mm

Hole length = 100 mm

elasticity for the aluminum is 85GN/m² = 85 × 10³ N/mm²

compressive load P = 180 KN = 180  × 10³ N

Calculate the total contraction on the bar = ???

The relation used in  calculating the contraction on the bar is:

\delta L = \dfrac{P *L }{A*E}

The relation used in  calculating the total contraction on the bar can be expressed as :

Total contraction in the Bar = (contraction in part of bar without hole + contraction in part of bar with hole)

i.e

Total contraction on the Bar = \dfrac{P *L_1 }{A_1*E} +  \dfrac{P *L_2 }{A_2 *E}

Let's find the area of cross section without the hole and with the hole

Area of cross section without the hole is :

Using A = πd²/4

A = π (40)²/4

A = 1256.64 mm²

Area of cross section with the hole is :

A = π (40²-30²)/4

A = 549.78 mm²

Total contraction on the Bar = \dfrac{P *L_1 }{A_1*E} +  \dfrac{P *L_2 }{A_2 *E}

Total contraction on the Bar  = \dfrac{180 *10^3 \N  }{85*10^3 \ N/mm^2} [\dfrac{500}{1256.64}+ \dfrac{100}{549.78}]

Total contraction on the Bar  = 2.117( 0.398 + 0.182)

Total contraction on the Bar  = 2.117*(0.58)

Total contraction on the Bar  = 1.22786 mm

5 0
3 years ago
Which of the following is most useful to determine how much energy is being used by a circuit in a given amount of time?
user100 [1]

Answer:

The answer is A.

Explanation:

5 0
3 years ago
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