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Blababa [14]
2 years ago
15

Gwen runs back and forth along a straight track. During the time interval 0≤t≤45 seconds, gwen’s velocity, in feet per second, i

s modeled by the function v given by v(t)=250sin(t2120)t 6
Physics
1 answer:
Vesnalui [34]2 years ago
8 0

Gwen's position is a function of his velocity and time

Gwen's position at 45 seconds is 63.9 feet

<h3>How to determine Gwen's position at 45 seconds?</h3>

The function is given as:

v(t) = 250sin(t^2/120)/(t + 6)

When t = 45, we  have:

v(45) = 250sin(45^2/120)/(45 + 6)

Evaluate the sum, the exponent and the quotient

v(45) = 250sin(16.875)/(51)

Evaluate the sine ratio

v(45) = 250 * 0.2903/51

Evaluate the product and quotient

v(45) = 1.42

The position is then calculated as:

S(45) = v(45) * 45

This gives

S(45) = 1.42 * 45

Evaluate the product

S(45) = 63.9

Hence, Gwen's position at 45 seconds is 63.9 feet

Read more about velocity function at:

brainly.com/question/10962624

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