Gwen's position is a function of his velocity and time
Gwen's position at 45 seconds is 63.9 feet
<h3>How to determine Gwen's position at 45 seconds?</h3>
The function is given as:
v(t) = 250sin(t^2/120)/(t + 6)
When t = 45, we have:
v(45) = 250sin(45^2/120)/(45 + 6)
Evaluate the sum, the exponent and the quotient
v(45) = 250sin(16.875)/(51)
Evaluate the sine ratio
v(45) = 250 * 0.2903/51
Evaluate the product and quotient
v(45) = 1.42
The position is then calculated as:
S(45) = v(45) * 45
This gives
S(45) = 1.42 * 45
Evaluate the product
S(45) = 63.9
Hence, Gwen's position at 45 seconds is 63.9 feet
Read more about velocity function at:
brainly.com/question/10962624