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Fudgin [204]
3 years ago
8

Why speed is a derived quantity?​

Physics
1 answer:
STatiana [176]3 years ago
3 0

Answer:

Explanation:

The speed is a derived quantity as it being derived from a defined set of quantities through a formula. There are only 7 fundamental quantities which are being defined with their individual fundamental units. Of those, length and time are two of them.Thus, it is a derived quantity

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What is the frequency of a light wave that has a wavelength of 0.039 m?
lyudmila [28]

Answer:

Convert your wavelength into meters. Divide the speed of light, ~300,000,000 m/s, by the wavelength in m. This gives you the wave's frequency

Explanation:

5 0
2 years ago
A house is maintained at 1 atm and 24°C. Outdoor air at 5.5°C infiltrates into the house through the cracks and warm air inside
Lunna [17]

Answer:

5454gjb

Explanation:

512212njun][[]

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3 years ago
Use the ratio version of Kepler’s third law and the orbital information of Mars to determine Earth’s distance from the Sun. Mars
frez [133]

Answer:

<em>1.49 x </em>10^{11}<em></em>

<em></em>

Explanation:

Kepler's third law states that <em>The square of the orbital period of a planet is directly proportional to the cube of its orbit.</em>

Mathematically, this can be stated as

T^{2} ∝ R^{3}

<em>to remove the proportionality sign we introduce a constant</em>

T^{2} = kR^{3}

k = \frac{T^{2} }{R^{3} }

Where T is the orbital period,

and R is the orbit around the sun.

For mars,

T = 687 days

R = 2.279 x 10^{11}

for mars, constant k will be

k = \frac{687^{2} }{(2.279*10^{11}) ^{3} } = 3.987 x 10^{-29}

For Earth, orbital period T is 365 days, therefore

365^{2} = 3.987 x 10^{-29} x R^{3}

R^{3} = 3.34 x 10^{33}

R =<em> 1.49 x </em>10^{11}<em></em>

8 0
3 years ago
Read 2 more answers
3/8 of light initial intensity is absorbed in the breaker with length of 2cm filled with 9% solution. Find the length of the bea
Rasek [7]

Answer:

Assume I1 = Io * T1        transmission proportional to thickness

I2 = Io * T2          I is intensity of light absorbed     (3/8 absorbed)

I1 / I2 = T1 / T2

T2 = T1 * (I2 / I1) = 2 * (2/3 / 3/8) = 2 * 16/9 = 32/9   thickness for 2/3 absorbed

3 0
3 years ago
It's nighttime, and you've dropped your goggles into a 3.2-m-deep swimming pool. If you hold a laser pointer 1.2 m above the edg
NNADVOKAT [17]

Answer:

Explanation:

Laser angle with water surface is given by: Tan α = 1/2.0= 0.5/

α = 26.56°

Laser angle with Normal = 90 - 26.56 = 63.44 °

Assuming a red laser, refractive index in water is 1.331.

Angle of refraction in water is given by:

Ref Ind = Sin i / Sin r

1.331 = Sin 63.44 / Sin r

Sin r = 0.8945 / 1.331 = 0.6721

Angle r = 42.22°

For the path in water:

Tan 42.22 = x / 3.2

x = 2.9m where x is the lateral displacement of the laser ince it hits the water

So the goggles are 2.0 + 2.9 = 4.9 m from edge of pool

5 0
3 years ago
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