Answer:
V = 576 V
Explanation:
Given:
- The area of the two plates A = 0.070 m^2
- The space between the two plates d = 6.3 mm
- Te energy density u = 0.037 J /m^3
Find:
- What must the potential difference between the plates V?
Solution:
- The energy density of the capacitor with capacitance C and potential difference V is given as:
u = 0.5*ε*E^2
- Where the Electric field strength E between capacitor plates is given by:
E = V / d
Hence,
u = 0.5*ε*(V/d)^2
Where, ε = 8.854 * 10^-12
V^2 = 2*u*d^2 / ε
V = d*sqrt ( 2*u / ε )
Plug in values:
V = 0.0063*sqrt ( 2 * 0.037 / (8.854 * 10^-12) )
V = 576 V
Answer
Explanation
Hope this helps you.
Let me know if you have any other questions :-):-)
Helium, neon and Xeon belong to the same Column( Group) which is Column 18 or you can say Group 8 in roman numbers
don't forget if you say group you should write in roman numbers okay. Best of luck
Answer:
I know the first one is C.) 4J. I don't know of the answer for the second oneis suppose to be in N/m form? but I got
2,500N/m
