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2 years ago

11

"Consider the Earth and the Moon as a two-particle system. (a) How far from the center of the Earth is the gravitational field o

f this two-particle system zero?"

1 answer:

olga55 [171]2 years ago

3 0

a is the correct

Explanation:

hope you like then comment

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What is the kinetic energy of a 74.0 kg skydiver falling at a terminal velocity of 52.0m/s?

skad [1K]

Answer:

100,048

Explanation:

K.E = 1/2 m (v)^2

K.E = 1^/2 * 74 * (52)^2

K.E = 100,048J =100.048kJ

8 0

3 years ago

5. A single slit illuminated with a 500 nm light gives a diffraction pattern on a far screen. The 5th minimum occurs at 7.00° aw

abruzzese [7]

For a single slit illuminated with a 500 nm light gives a diffraction pattern on a far screen,the angle is mathematically given as

theta=25.3

Option A is correct

<h3> What angle does the 18th minimum occur?</h3>

Generally, the equation for the the angle is mathematically given as

$\theta=n(\lambda/d)$

Therefore

$\theta 1/ \theta 2=n1(\lambda/d)/ n2(\lambda/d)$

In conclusion

theta/7=16/5

theta=10*7/5

theta=25.3

Read more about Angle

brainly.com/question/14362353

3 0

2 years ago

An object, initially at rest, moves 250 m in 17 s. What is its acceleration?

mash [69]

Answer:

1.73 m/s²

Explanation:

Given:

Δx = 250 m

v₀ = 0 m/s

t = 17 s

Find: a

Δx = v₀ t + ½ at²

250 m = (0 m/s) (17 s) + ½ a (17 s)²

a = 1.73 m/s²

5 0

2 years ago

A stone on ground is zero energy

NNADVOKAT [17]

Answer:

A stone on the ground does not have zero energy…there is an internal potential in every object. Aldo is not in action or in any mechanical motion it is being acted upon by gravity and also molecular forces and energy.

<em>Hope</em><em> </em><em>this</em><em> helps</em><em> </em><em>!</em>

7 0

3 years ago

An object accelerating at 16 m/s/s doubles its mass and triples its net force acting on it. What will the new acceleration be? (

nataly862011 [7]

Answer:

24 m/s²

Explanation:

The given parameters are;

The initial acceleration of the object, a = 16 m/s²

Let 'm' represent the initial mass of the object

The initial force acting on the object, F = m × a

∴ F = 16 × m = 16·m

When the mass is doubled, we have;

The new mass of the object, m₂ = 2 × m = 2·m

When the net force acting on the object triples, we have;

The new net force acting on the object, F₂ = 3 × F = 3 × 16·m = 48·m

From F = m × a, we have;

a = F/m

∴ The new acceleration of the object, a₂ = F₂/m₂

From which, by plugging in the values, we have;

a₂ = 48·m/(2·m) = 24

The new acceleration of the object, a₂ = 24 m/s².

6 0

3 years ago