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VikaD [51]
3 years ago
9

Given the function f(x) = –0. 5|2x 2| 1, for what values of x is f(x) = 6? x = 6, x = –5 x = 5, x = –5 x = 7, x = –6 no solution

.
Mathematics
1 answer:
maria [59]3 years ago
7 0

There is no solution for the given function \rm f(x) = -0.5|2x+2|+1 when f(x) = 6 option fourth is correct.

It is given that the function  \rm f(x) = -0.5|2x+2|+1

It is required to find the values of x when f(x) = 6

<h3>What is a function?</h3>

It is defined as a special type of relationship and they have a predefined domain and range according to the function.

We have a function:

\rm f(x) = -0.5|2x+2|+1

And f(x) = 6

Putting the value of f(x) in the above equation, we get:

\rm 6 = -0.5|2x+2|+1   or

\rm  -0.5|2x+2|+1= 6\\\\\rm  -0.5|2x+2|= 6-1\\\\\rm  -0.5|2x+2|+5\\\\\rm |2x+2|= \frac{5}{-0.5} \\\\\rm |2x+2|= -10

Here we can see the mod function values is negative which is not possible, hence there is no solution for the above equation for any 'x'

Thus, there is no solution for the given function \rm f(x) = -0.5|2x+2|+1 when f(x) = 6.

Learn more about the function here:

brainly.com/question/5245372

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Answer:

65.46 units

Step-by-step explanation:

Given the information:

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Let x is the length of the leg side (x>0)

We use cosine law to find x, we have:

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3 years ago
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Jobisdone [24]
<span>Data:
</span><span>Hypotenuse is 7.5 
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Cosine = Side opposite (S.O) the angle on the hypotenuse (h)

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</span>Cos (\alpha)x =  \frac{S.O}{h}
Cos (\alpha)x = \frac{6}{7.5}
\boxed{Cos (\alpha)x = 0.8}

<span>For better understanding, see the annex:

</span>

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