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alexandr1967 [171]
3 years ago
10

These goats are eating grass on a sunny day. What is happening to the carbon in the air around the living things on the mountain

? Is carbon moving into the air, moving out of the air, or both?.
Chemistry
1 answer:
polet [3.4K]3 years ago
8 0

Answer:

both

Explanation:

Carbon in the air around the living thing is moving in and out of its lungs. The movement is occurring at the same time. This is one of the most important gaseous exchange important to life.

  • The goats takes in oxygen gas from the surrounding and releases carbon dioxide in the process.
  • But, air is actually drawn in by the goat which is a mixture of several gases.
  • Air contains carbon dioxide which is a rich source of carbon
  • With the carbon dioxide from respiratory processes, the goat ejects and breathes out this waste carbon matter.
  • Therefore, the gaseous exchange in a goat involves the movement of carbon in and out of the air.
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If you have a gold brick that is 2cm by 3cm by 4cm and has density of 19.3g/cm3, what is its mass?
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Volume = a x a x a  

V = 2 cm x 3 cm x 4 cm => 24 cm³

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m = D x V

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2 years ago
"11. Barium nitrate reacts with aqueous sodium sulfate to produce solid barium sulfate and aqueous sodium nitrate. Abigail place
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Answer:

44 mL of Na2SO4

Explanation:

Step 1:

The balanced equation for the reaction. This is given below:

Ba(NO3)2 (aq) + Na2SO4 (aq) —> BaSO4 (s) + 2NaNO3 (aq)

Step 2:

Determination of the number of mole of Ba(NO3)2 in 20.00 mL of 0.500 M barium nitrate (Ba(NO3)2). This is illustrated below:

Molarity of Ba(NO3)2 = 0.5 M

Volume of solution = 20 mL = 20/1000 = 0.02 L

Mole of solute (Ba(NO3)2) =?

Molarity = mole /Volume

0.5 = Mole of Ba(NO3)2 / 0.02

Cross multiply to express in linear form

Mole of Ba(NO3)2 = 0.5 x 0.02

Mole of Ba(NO3)2 = 0.01 mole

Step 3:

Determination of the number of mole of Na2SO4 that reacted.

Ba(NO3)2 (aq) + Na2SO4 (aq) —> BaSO4 (s) + 2NaNO3 (aq)

From the balanced equation above,

1 mole of Ba(NO3)2 reacted with 1 mole of Na2SO4.

Therefore, 0.01 mole of Ba(NO3)2 will also react with 0.01 mole of Na2SO4.

Step 4:

Determination of the volume of Na2SO4 needed for the reaction. This is illustrated below:

Mole of Na2SO4 = 0.01 mole

Molarity of Na2SO4 = 0.225M

Volume =?

Molarity = mole /Volume

0.225 = 0.01 / volume

Cross multiply to express in linear form

0.225 x Volume = 0.01

Divide both side by 0.225

Volume = 0.01/0.225

Volume of Na2SO4 = 0.044 L

Converting 0.044 L to mL, we have

Volume of Na2SO4 = 0.044 x 1000

Volume of Na2SO4 = 44 mL

Therefore, 44 mL of Na2SO4 is needed for the reaction

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3 years ago
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Answer:

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Explanation:

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Answer:

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Explanation:

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