The two control bases would be water and salt.
The question is incomplete. The complete question is attached below.
Answer : The correct option is, (A) 7-chloro-3-ethyl-4-methyl-3-heptene
Explanation :
The rules for naming of alkene are :
First select the longest possible carbon chain.
The longest possible carbon chain should include the carbons of double bonds.
The naming of alkene by adding the suffix -ene.
The numbering is done in such a way that first carbon of double bond gets the lowest number.
The carbon atoms of the double bond get the preference over the other substituents present in the parent chain.
If two or more similar alkyl groups are present in a compound, the words di-, tri-, tetra- and so on are used to specify the number of times of the alkyl groups in the chain.
The given compound name will be, 7-chloro-3-ethyl-4-methyl-3-heptene.
The structure of given compound is shown below.
Standard Temperature and Pressure (STP) is defined as 0 degrees Celsius and 1 atmosphere of pressure.
Less than that of nitrogen and oxygen remember cnof "see noff" . this is the order of electronegativity carbon is less than nitrogen which is less than oxygen which is less than fluorine.
Answer:
48.84mL
Explanation:
H2SO4 + 2KOH → K2SO4 + 2H2O
From the question:
nA = 1
nB = 2
From the question given we obtained the following information:
Ma = 0.43M
Va =?
Mb = 0.35M
Vb = 120mL
Using MaVa / MbVb = nA/nB, we can easily find the volume of the acid required. This is illustrated below:
MaVa / MbVb = nA/nB
0.43 x Va / 0.35 x 120 = 1/2
Cross multiply to express in linear form
2 x 0.43 x Va = 0.35 x 120
Divide both side by the (2 x 0.43)
Va = (0.35 x 120) /(2 x 0.43)
Va = 48.84mL
Therefore, the volume of H2SO4 required is 48.84mL