Answer:

Explanation:
First, we find in the tables the ΔH of formation of each compound. As you can see in the (image 1)
Then we solve the ecuation for ΔH°reaction
ΔH°reaction=∑ΔH°f(products)−∑ΔH°f(Reactants)
ΔH°reaction= (-2* 393.5 - 2*285.8) - (52.4 + 0) kJ/mol
ΔH°reaction = -1.41 *10^3 kJ/mol
Answer:
Yes Concurred,but where is the question
<span>The solution to the problem is as follows:
125/58.69 = 2.12 mol
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Therefore, there are 2.12 moles of <span>nickel (Ni) atoms are in 125 g Ni.
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The given molarity of sodium hydroxide solution = 2.0 M
The required concentration of sodium hydroxide is 65 mL of 0.6 M NaOH
Converting 65 mL to L:

Calculating the moles of NaOH in the final solution:

Finding out the volume of 2.0 M solution taken to prepare the final solution:

Therefore, 19.5 mL of 2.0 M NaOH solution and make it up to 65 mL to prepare 0.6 M NaOH solution.
There is fr-218
hope this did the job, have a nice rest of your day!!