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nikitadnepr [17]
3 years ago
5

How many cm is equal to 1450 nm?

Chemistry
1 answer:
grigory [225]3 years ago
3 0

Answer:

The answer is D; 1.45 x 10^-4

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What equation in the blast furnace extraction of iron is not a redox reaction?
Misha Larkins [42]

The decomposition of limestone CaCO3 > CaO + CO2

8 0
3 years ago
An estser is the reaction product between: a. Alcohol and organic acid
san4es73 [151]
An ester is the reaction product between A. alcohol and organic acid. 
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3 years ago
Urea, CO(NH2)2, is manufactured on a large scale for use in producing urea-formaldehyde plastics and as a fertilizer. What is th
Pachacha [2.7K]

Answer:

5.004kg

Explanation:

Combustion of carbon

C+O2=CO2

from the relationship of molar ratio

mass of carbon/molar mass of carbon=volume of CO2 produced\molar vol(22.4 dm3)

mass of carbon =1000kg

atomic mass of carbon =12

volume of CO2 produced=1000×22.4/12

volume of CO2 produced =1866.6dm3

from the combustion reaction equation provided

CO2 (g) + 2NH3 (g) ⟶ CO (NH2 )2 (s) + H2 O(l)

applying the same relationship of molar ratio

no of mole of CO2=no of mole of urea

therefore

vol of CO2\22.4=mass of urea/molar mass of urea

molar mass of urea=60.06g/mol

from the first calculation

vol of CO2=1866.6dm3

mass of urea=1866.6×60.06/22.4

mass of urea=5004.82kg

7 0
3 years ago
Read 2 more answers
How many 20.0-g ice cubes are required to absorb 47.0 kJ from a glass of water upon melting?
Sati [7]

Hello!


The number of 20-g ice cubes required to absorb 47 kJ from a glass of water upon melting is 7 icecubes


Why?


We are going to clear from the equation of the released heat, the mass of ice (m). The specific latent heat of fusion of ice is 336 kJ/kg:


Q=m*L\\ \\ m=\frac{Q}{L}=\frac{47 kJ}{336 kJ/kg}=0,1399 kg=139,88 g\\   \\ 139,88g*\frac{1 icecube}{20g}=6,99=7icecubes


So, 7 ice cubes are required to absorb that amount of heat from the glass of water.


Have a nice day!

3 0
3 years ago
The concentration of sugar in Coke is approximately 10%, or 100 ppt. If you drink
masya89 [10]

Answer:

35.5g of sugar

Explanation:

To solve this question we must assume the density of coke = Density of water = 1g/mL

Thus, in a single can of coke, the mass is 355g. Now, the 10% of this coke is sugar. That means the amount of sugar you are consuming is:

355g * (10/100) = 35.5g of sugar

<em>10/100 = 10%</em>

7 0
3 years ago
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