Copper has a density of 8.9 g cm3. if you have 90 g of copper how much volume is your occupying?

At T = 250 °C the reaction PCl5(g) PCl3(g) + Cl2(g) has an equilibrium constant in terms of pressures Kp = 2.15. (a) Suppose the

Ganezh [65]

Answer:

To the right

Explanation:

Step 1: Given data

Partial pressure of PCl₅ (pPCl₅) = 0.548 atm

Partial pressure of PCl₃ (pCl₃) = 0.780 atm

Partial pressure of Cl₂ (pCl₂) = 0.780 atm

Step 2: Write the balanced equation

PCl₅(g) ⇄ PCl₃(g) + Cl₂(g)

Step 3: Calculate the pressure reaction quotient

$Q_p = \frac{pPCl_3 \times pCl_2 }{pPCl_5} = \frac{0.780 \times 0.780 }{0.548} =1.11$

Step 4: Determine whether the reaction proceeds to the right or to the left as equilibrium is approached

Since <em>Qp < Kp</em>, the reaction will proceed to the right to attain the equilibrium.

7 0

3 years ago

Which member of each pair is the stronger base? part a ethylamine or aniline ethylamine or aniline ethylamine aniline request an

Vladimir79 [104]

Lowery-Bronsted theory is applied here. Acc. to this theory Base accepts protons and Acids donate proton.

Part 1:
Aniline is less basic than ethylamine because the lone pair on nitrogen (which accepts proton) is not localized. It resonates throughout the conjugated system of phenyl ring. Hence due to unavailability of electrons for accepting proton it is less basic compare to ethylamine. In ethyl amine the lone pair of electron is localized and available to abstract proton.

Part 2:
In this case the alkyl groups attached to -NH₂ (in ethylamine) and -O⁻ (in ethoxide are same (i.e. CH₃-CH₂-). Ethoxide is more basic than ethylamine because ethoxide is a conjugate base of ethanol (pKa value of ethanol = 15.9 very weak acid) and the conjugate base of weak acid is always a strong base. Secondly, the oxygen atom more Electronegative than Nitrogen atom can attract more electron cloud from alkyl group as compared to Nitrogen in ethylamine. Hence, oxygen in ethoxide attains greater electron cloud than the nitrogen in ethylamine. Therefore, it is more basic than ethylamine.

5 0

3 years ago

Use the "x is small" approximation to find the concentration of the products in the following reaction which initially contains

Mrrafil [7]

Answer:

Concentration of product at equilibrium ;

$[H^+]=0.0000229 M$

$[CN^-]=0.0000229 M$

Explanation:

$HCN(aq)\rightleftharpoons H^+(aq) + CN^-(aq)$

initially

0.85 M 0 0

(0.85-x)M x x

The equilibrium constant of reaction = $K_c= 6.17\times 10^{-10}$

The expression of an equilibrium cannot can be written as:

$K_c=\frac{[H^+][CN^-]}{[HCN]}$

$6.17\times 10^{-10}=\frac{x\times x}{(0.85-x)}$

Solving for x:

x = 0.0000229

Concentration of product at equilibrium ;

$[H^+]=0.0000229 M$

$[CN^-]=0.0000229 M$

4 0

2 years ago

How do you scientist learn about the moon in other planets

Citrus2011 [14]

Answer:NASA's Lunar Atmosphere and Dust Environment probe, for instance, orbits the moon and collects information about its atmosphere and surface. This important data can help scientists learn more about moons, asteroids and other objects in the solar system.

Explanation:

8 0

3 years ago

2. What is the molarity of a HCl solution containing 1.2 grams of hydrochloric acid in 0.025 L of solution?

alisha [4.7K]

Answer:

1.3M

Explanation:

Convert from grams to moles:

molar mass of HCl = 1.01g(molar mass of H) + 35.45g(molar mass of Cl) = 36.46g HCl

1.2g HCl (1mol HCl/36.46g HCl)

= .0329 mol HCl

Molarity = mol/L (important formula for concentration)

Plug your values in:

Molarity = .0329mol/.025L

1.317M - but you used two significant figures in the question, so:

1.3M

3 0

3 years ago