Well, first of all, if the ramps are perfectly frictionless, then the ball
won't roll ... it'll slide. Kind of like a bowling ball does at the beginning
of a shiny, highly-waxed lane. You need friction against the ball to roll it.
But in any case, no matter what the slopes of the ramps are, even
if they have different slopes, the ball will rise on the second ramp
to the same height from which it was released on the first ramp.
Answer: time taken to charge to 95%
t = -5.80[ln(1-0.95)]
t = 17.38ms
Explanation:
For an RC Charging circuit
Where Vs
Vc = Vs (1 - e^(-t/RC))
Vc/Vs = 1 - e^(-t/RC)
-t/RC = ln(1 - Vc/Vs)
t = -RC[ln(1 - Vc/Vs)] and RC = k = -t/ln(1 - Vc/Vs)
Where ;
Vc = voltage across the capacitor
Vs = voltage supply
t = charging time = 2.5ms
k = RC = time constant.
Vc/Vs = 0.35
To calculate the time constant k;
k = -t/ln(1- Vc/Vs)
k = -2.5/ln(1-0.35)
k = 5.80ms
time taken to charge to 95%
t = -5.80[ln(1-0.95)]
t = 17.38ms
Answer:
First you fond the total force the car initialy has which is F=ma so it is 1500 times 8 which leads you to get 12000N then you divide the force of the car by the breaks and the road (4200N) which gives you 2.85 seconds for the car to come to a stop.
Option C. inferential statistics
Trying to reach conclusions that extend beyond immediate data alone. This is used also in making judgments of the probability that an observed difference between groups is a dependable one. Therefore, using this is to arrive an inferences from our data in a more general conditions.
