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Fed [463]
2 years ago
12

A bad contains 15 balls of which X is red. Write an expression for the probability that a ball drawn from the bad is red. When 5

more red balls are added to the bag, the probability becomes 3/4. Find the value of X.

Mathematics
1 answer:
antoniya [11.8K]2 years ago
5 0

Answer:

10

Step-by-step explanation:

The current probability of picking a red ball is \frac{x}{15}. When 5 more balls are added, the probability is 3/4. We can write a ratio for this problem:

\frac{x+5}{15+5} = \frac{3}{4}

When using cross multiplication to solve this, you get 3 * 20 = 4(x+5).

60 = 4x + 20

40 = 4x

x = 10 red balls

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At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is
Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = \frac{dx}{dt}

ship B is sailing north at 20 km/h =\frac{dy}{dt}

here x and y are the  sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

                 y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find \frac{dz}{dt} at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we |  | get \\

z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h

derivative first equation w . r. to t we get

2z\frac{dz}{dt} =-2(130-x)\frac{dx}{dt}+2y\frac{dy}{dt}

\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]

\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }

     = \frac{1100}{85.44}\\  = 12.87km/h

8 0
3 years ago
Find the length of AB
hjlf

Answer:

the answer is 36centameters

3 0
3 years ago
Y
irakobra [83]
What is the question??
7 0
3 years ago
An aeroplane is flying due north but, to avoid a storm, it flies 150km
Nataly [62]

Answer:

1) angle ABC = 80°

angle ACB = 40°

2) extra distance traveled = 122 km

Step-by-step explanation:

From the image, angle p° will be equal to 60° (alternate angles).

Angle t° will be equal to (90 - 60) = 30°.

Angle r° = (320 - 270) = 50°

Therefore angle ABC = angle (r° + t°) = (50 + 30) = 80°

BCD is a right angle triangle, therefore, the two other angles apart from the right angle must sum up to 90°.

BCD = ACB = (90 - 50) = 40°

lenght of DB is calculated as

sin 60 = DB/150

0.866 = DB/150

DB = 0.866 X 150 = 129.9 km

AD^2 = 150^2 - 129.9^2 = 5625.99 km

AD = 75 km

Tan 50 = CD/129.9

1.192 =CD/129.9

CD = 129.9 X 1.192 = 154.84 km

BC^2 = 154.84^2 + 129.9^ = 40849.44

BC = 202.11 km

If the plane had flown due north it would have covered AD + CD = 75 + 154.84 = 229.84 km

The divertion took a total distance of AB + BC = 150 + 202.11 = 352.11 km

The extra distance is 352.11 - 229.84 = 122.27 km

Approximately 122 km

4 0
3 years ago
The distance between the library and town hall is 735 ft the actual distance is 612 ft what is the percent error. Round your ans
tatyana61 [14]

well, we know the actual distance is 612, however the estimate is 735, is off by 735 - 612 = 123.

now if we take 612 to be the 100%, what is 123 off of it in percentage?

\bf \begin{array}{ccll} amount&\%\\ \cline{1-2} 612&100\\ 123&x \end{array}\implies \cfrac{612}{123}=\cfrac{100}{x}\implies \cfrac{204}{41}=\cfrac{100}{x}\implies 204x=4100 \\\\\\ x = \cfrac{4100}{204}\implies x = \cfrac{1025}{51}\implies x \approx 20.098

5 0
3 years ago
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