(c)p→π⁺₊π⁺₊π
Baryon number is +1 on the left side of the equation, 0 on the
right side. Baryon number is not conserved.
<h3>How do you determine whether a baryon number is conserved?</h3>
- According to the law of conservation of baryon number, the sum of the baryon numbers of all incoming particles equals the sum of the baryon numbers of all particles produced by the reaction. Energy, and so on, are conserved even if the incoming proton has sufficient energy and charge.
<h3>What is Baryon Number</h3>
- In particle physics, the baryon number denotes which particles are baryons and which particles are not. Each baryon has a baryon number of 1, and each antibaryon has a baryon number of -1. Other non-baryonic particles have a baryon number of 0. Since there are exotic hadrons like pentaquarks and tetraquarks, there is a general definition of baryon number as:
- B=1/3(
)
- where
represents the number of quarks and nq represents the number of antiquarks.
To learn more about Baryon Number refer to
brainly.com/question/10358797
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Answer:
<h3>a.</h3>
- After it has traveled through 1 cm :

- After it has traveled through 2 cm :

<h3>b.</h3>
- After it has traveled through 1 cm :

- After it has traveled through 2 cm :

Explanation:
<h2>
a.</h2>
For this problem, we can use the Beer-Lambert law. For constant attenuation coefficient
the formula is:

where I is the intensity of the beam,
is the incident intensity and x is the length of the material traveled.
For our problem, after travelling 1 cm:




After travelling 2 cm:




<h2>b</h2>
The optical density od is given by:
.
So, after travelling 1 cm:




After travelling 2 cm:




Answer: frequency f = 2000 1/s (Hz)
Explanation: period T means time for one cycle and frequency f tells how many cycles there are in seconds. Unit of frequency is 1/s= Hz. Period T = 1/f and frequency f= 1/T.
E.g is T= 0.01 s then f= 1/ (0.01 s) = 100 Hz. And I'd frequency is 20 Hz,
T= 1/(20 Hz)= 0.05 s. So, if T = 0.005 s, f= 1/T