Answer:
(a) The probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b) The probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Step-by-step explanation:
Let the random variable <em>X</em> follow a Normal distribution with parameters <em>μ</em> = 155.4 and <em>σ</em> = 49.5.
(a)
Compute the probability that a single randomly selected value lies between 158.6 and 159.2 as follows:

*Use a standard normal table.
Thus, the probability that a single randomly selected value lies between 158.6 and 159.2 is 0.004.
(b)
A sample of <em>n</em> = 246 is selected.
Compute the probability that a sample mean is between 158.6 and 159.2 as follows:

*Use a standard normal table.
Thus, the probability that a sample mean is between 158.6 and 159.2 is 0.0411.
Ur basically looking for the common multiple of the numbers 8,9,12,and 15.
LCM of these numbers is 360.
so 360 minutes = (360/60) = 6 hrs
and 6 hrs from 3 p.m. would be : 9 p.m. <== ur answer
Answer:
3 1/2 Pounds
Step-by-step explanation:
2/3=4/6
4/6+5/6=9/6
30/6-9/6=21/6
This would be A True, hope this helps !
Answer:
The correct answer was
1=Zero product property
2=square root property
Step-by-step explanation: