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kenny6666 [7]
4 years ago
11

How many electrons can each orbital hold?

Chemistry
1 answer:
Leokris [45]4 years ago
7 0
S orbital can hold 2
P can hold 6
D can hold 10
F can hold 14
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PLEASE HELP!!!!!!!
shusha [124]

Answer:

impacts on visiters

Explanation:

hope this is right sorry if its not

Joshua Tree suffers from air pollution and smog blowing into the park. Increased warming from climate change worsens the visibility from smog and air pollution, due to the chemistry of how smog reacts to heat.

4 0
2 years ago
Write the name of the metric system prefix associated with each mathematical factor. Do not use any hyphens in your answers and
MrRissso [65]

Answer:

1. micro

2. centi

3. milli

4. kilo

Explanation:

Prefixes, in mathematical exponents, are defined as the alphabetical names associated with the mathematical factors. Some examples are as follows:

10⁶ = Mega

10⁹ = Giga

10⁻⁹ = Nano

10⁻¹² = Pico

So, in order to name the metric system prefixes associated with each of the given mathematical factor, we first convert the factor into exponent form and then write its prefix, as follows:

10⁻⁶ = <u>micro</u>

1/100 = 0.01 = 1 x 10⁻² = <u>centi</u>

0.001 = 1 x 10⁻³ = milli

1000 = 1 x 10³ = <u>kilo</u>

8 0
3 years ago
True or False Decreasing the temperature and movement of particles will speed up the reaction rate.
marissa [1.9K]

I think it's True hope it helps

5 0
3 years ago
I had graduated cylinder with 50 mL of water. I added a rock to the graduated cylinder and the water level rose to 56 mL. What i
jeka57 [31]
Take 56 mL and subtract the original volume of 50 mL and that will give you the volume of the rock, which is 6mL.
8 0
3 years ago
How many joules are required to raise the temperature of a 6.50 g sample of silver from 34°c to 189°C? The specific heat of gold
nata0808 [166]

Answer:

236.76 J

Explanation:

Parameters given:

Mass of sample, m = 6.50 g

Initial temperature, T_1 = 34^o C

Final temperature, T_2 = 189^oC

Specific heat capacity of gold, c = 0.235 J/g^oC

Heat of a substance is related to specific heat capacity by the formula:

H = mc(T_2 - T_1)

H = 6.5 * 0.235 * (189 - 34)\\\\\\H = 6.5 * 0.235 * 155\\\\\\H = 236.76 J

236.76 J of heat is required to raise the temperature of the sample.

5 0
4 years ago
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