4. Pb +FeSO, - PbSO, +Fe Reaction Type:

What happens when magma cools either underground or on the surface and hardens?

exis [7]

I think it turns into an igneous rock

6 0

2 years ago

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There are 360 degrees in a circle. How many arcminutes will be in 86% of a circle?

Leokris [45]

Answer:

There are 18572.9 arcminutes in 86% of a circle.

Explanation:

The degrees in 86% of a circle is:

$degrees = \frac{86}{100}*360 = 309.6 ^{\circ}$

Now, we need to find the number of arcminutes in 309.6°:

$arcminute = \frac{59.99 arcminute}{1 degree}*309.6 degrees = 18572.9$

Therefore, there are 18572.9 arcminutes in 86% of a circle.

I hope it helps you!

3 0

3 years ago

Cassidee walks 1-mile north and then turns and walks 2 miles west. Distance Displacement

Gemiola [76]

Answer:

3 miles?

Explanation:

if you walk one mile North and then turn and walk another two miles you walk 3 miles and then turn around and walk back in the same direction you would end backup at the one-mile Mark he began. So three miles there two miles back

4 0

1 year ago

How many moles are in 1.2x10^3 grams of ammonia, NH3?

KonstantinChe [14]

I don't have a calculator with me right now, but that mass would be 1200 grams. Divide the given amount of grams by the molar mass of NH3, which is 17.031g/mol. (Nitrogen + 3(hydrogen)). Again, sorry I didn't have a calculator. But all you would need to do is divide 1200 by 17.031. If you need to use sig figs, your answer should have 2 because the 1.2 x 10^3 limits your amount of sig figs.

6 0

3 years ago

An aqueous solution containing 10 g of an optically pure compound was diluted to 500 mL with water and was found to have a speci

lapo4ka [179]

Answer:

Optical purity = 76.9231 %

Specific rotation of mixture = - 97.6923 °

Explanation:

The mass of the racemic mixture = 3 g

It means it contains R enantiomer = 1.5 g

S enantiomer = 1.5 g

Amount of Pure R = 10 g

Total R = 11.5 g

Total volume = 500 mL + 500 mL = 1000 mL = 1 L

[R] = 11.5 g/L

[S] = 1.5 g/L

Enantiomeric excess = $\frac {Excess}{Total\ Concentration}\times 100$ = $\frac {11.5-1.5}{11.5+1.5}\times 100$ = 76.9231 %

Optical purity = 76.9231 %

Also,

Optical purity = $\frac {optical\ rotation\ of\ mixture}{optical\ rotation\ of\ pure\ enantiomer}\times 100$

Optical rotation of pure enantiomer = −127 °

$76.9231=\frac {optical\ rotation\ of\ mixture}{-127^0}\times 100$

Specific rotation of mixture = - 97.6923 °

6 0

2 years ago