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Trava [24]
11 months ago
12

Q: Compare and contrast the different parts of the Electromagnetic Spectrum. Evaluate the usefulness of each part and decide whi

ch part is most useful, or most important, to you and society as a whole. You must provide two reliable sources to back up your opinion. Recall that reliable sources include scientific sites or publications, education sites or publications, and government sites or publications.
The purpose of this assignment is to debate and consider different opinions on this topic. There is no right or wrong answer. However, this discussion should represent varying opinions. You will need to do some research and back up your opinions with facts. Remember to cite your sources!

A: The different parts of the electromagnetic spectrum are ultraviolet lights, infrared lights, x-rays, gamma rays, and radio waves. All of these colors are called the electromagnetic spectrum. Each of these parts have different energy levels, wavelengths, and frequencies. According to scied.ucar,edu, Gamma rays have the highest energies and radio waves have the lowest. As imagine.gsfc.nasa.gov states, a comparison of all of the parts is that their radiations are defined by the amount of energy found in the photons. They will still have different energies but they all use photons. Usefulness for Radio: It captures radio waves emitted by radio station which makes our favorite tunes. Microwave: cooks popcorn in a few mins. Infrared: night vision goggles use this light. Helps us map dust between stars. Visible: Our eyes detect visible light. Fireflies, light bulbs, and stars all emit visible light. Ultraviolet:Emitted by sun and reason why skin tans and burns. X-ray:Dentist uses to view teeth, airport security to see through your bag, used to see inside things. Gamma ray: Doctors use it to image inside your body. I think the most important would be the visible ones because those are the ones everyone uses no matter what. If there was no light we wouldn't see. We can see light with our vision.
Physics
1 answer:
LUCKY_DIMON [66]11 months ago
3 0

The infrared and ultraviolet parts of the electromagnetic spectrum can be used in the field of chemical analysis.

The sections of the EM spectrum are named in order of increasing energy gamma rays X-rays ultraviolet-visible light infrared, and radio waves. Microwaves used in microwave ovens are a subsection of the radio segment of the EM spectrum.

Electromagnetic energy travels in waves and covers a wide spectrum from very long radio waves to very short gamma rays. The human eye can only see a small portion of this spectrum known as visible light. The electromagnetic spectrum includes all frequencies of electromagnetic radiation that carry energy and travel through space in the form of waves. Low frequencies and long wavelengths make up the radio spectrum.

Learn more about The Electromagnetic spectrum here:-brainly.com/question/23423065

#SPJ1

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What measurements or observations tells you that a car is accelerating
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8 0
3 years ago
Read 2 more answers
An object with 10 protons 14 electrons and 5 neutrons would have what charge
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Answer:-4

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10protone +10

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10-14=-4

7 0
2 years ago
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4 0
3 years ago
A 1.00 kg particle has the xy coordinates (-1.20 m, 0.500 m) and a 4.50 kg particle has the xy coordinates (0.600 m, -0.750 m).
just olya [345]

Answer:

a) The x coordinate of the third mass is -1.562 meters.

b) The y coordinate of the third mass is -0.944 meters.

Explanation:

The center of mass of a system of particles (\vec r_{cm}), measured in meters, is defined by this weighted average:

\vec r_{cm} = \frac{\Sigma_{i=1}^{n}\,m_{i}\cdot \vec r_{i}}{\Sigma_{i=1}^{n}\,m_{i}} (1)

Where:

m_{i} - Mass of the i-th particle, measured in kilograms.

\vec r_{i} - Location of the i-th particle with respect to origin, measured in meters.

If we know that \vec r_{cm} = (-0.500\,m,-0.700\,m), m_{1} = 1\,kg, \vec r_{1} = (-1.20\,m, 0.500\,m), m_{2} = 4.50\,kg, \vec r_{2} = (0.600\,m, -0.750\,m) and m_{3} = 4\,kg, then the coordinates of the third particle are:

(-0.500\,m, -0.700\,m) = \frac{(1\,kg)\cdot (-1.20\,m,0.500\,m)+(4.50\,kg)\cdot (0.600\,m,-0.750\,m)+(4\,kg)\cdot \vec r_{3}}{1\,kg+4.50\,kg+4\,kg}

(-4.75\,kg\cdot m, -6.65\,kg\cdot m) = (-1.20\,kg\cdot m, 0.500\,kg\cdot m) + (2.7\,kg\cdot m, -3.375\,kg\cdot m) +(4\cdot x_{3},4\cdot y_{3})

(4\cdot x_{3}, 4\cdot y_{3}) = (-6.25\,kg\cdot m,-3.775\,kg\cdot m)

(x_{3},y_{3}) = (-1.562\,m,-0.944\,m)

a) The x coordinate of the third mass is -1.562 meters.

b) The y coordinate of the third mass is -0.944 meters.

5 0
2 years ago
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