The speed of the wave with the given frequency and wavelength is 1.2m/s.
Given the data in the question;
- Wavelength of the wave;

- Frequency;

- Speed of the wave;

<h3>
Wavelength</h3>
Wavelength is the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.
It is expressed as;

Where v is velocity/speed and f is frequency.
Now, we can easily get the speed of the wave by substituting our given values into the expression above.

Therefore, the speed of the wave with the given frequency and wavelength is 1.2m/s.
Learn more about Speed, Frequency and Wavelength here: brainly.com/question/27120701
Answer:
The workdone by Jack is 
The workdone by Jill is 
The final velocity is 
Explanation:
From the question we are given that
The mass of the boat is 
The initial position of the boat is 
The Final position of the boat is 
The Force exerted by Jack 
The Force exerted by Jill 
Now to obtain the displacement made we are to subtract the final position from the initial position


Now that we have obtained the displacement we can obtain the Workdone
which is mathematically represented as
The amount of workdone by jack would be

![= [(-420\r i +0\r j +210\r k)(2\r i + 0\r j - \r k)]](https://tex.z-dn.net/?f=%3D%20%5B%28-420%5Cr%20i%20%2B0%5Cr%20j%20%2B210%5Cr%20k%29%282%5Cr%20%20i%20%2B%200%5Cr%20j%20-%20%5Cr%20k%29%5D)



The amount of workdone by Jill would be

![= [(180 \r i + 0\r j + 360\r k)(2\r i +0\r j -\r k)]](https://tex.z-dn.net/?f=%3D%20%5B%28180%20%5Cr%20i%20%2B%200%5Cr%20j%20%2B%20360%5Cr%20k%29%282%5Cr%20i%20%2B0%5Cr%20j%20-%5Cr%20k%29%5D)


According to work energy theorem the Workdone is equal to the kinetic energy of the boat
![W = K.E = \frac{1}{2} m *[v^2 - (1.1)^2]](https://tex.z-dn.net/?f=W%20%3D%20K.E%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20m%20%2A%5Bv%5E2%20-%20%281.1%29%5E2%5D)
![-1050 = 0.5*3300 [*v^2- (1.1)^2]](https://tex.z-dn.net/?f=-1050%20%20%3D%200.5%2A3300%20%5B%2Av%5E2-%20%281.1%29%5E2%5D)
![-1050 = 1650 [v^2 -1.21]](https://tex.z-dn.net/?f=-1050%20%3D%201650%20%5Bv%5E2%20-1.21%5D)




Answer:
An instrument for measuring the density of liquids.
Explanation:
A hydrometer is an instrument used to determine specific gravity. It operates based on the Archimedes principle that a solid body displaces its own weight within a liquid in which it floats. Hydrometers can be divided into two general classes: liquids heavier than water and liquids lighter than water.
Thermohydrometers is one type of hydrometer.