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Mariulka [41]
3 years ago
7

A 0.600 kg toy car is powered by one 9V battery (9.00 V) connected directly to a small DC motor. The car has an effective energy

conversion efficiency of 30.6 % , meaning that 30.6 % of the electric energy applied to the motor is converted into translational kinetic energy. After 5.69 s , the car, which is initially at rest, reaches a speed of 3.43 m / s . What is the average current supplied to the car's motor
Physics
1 answer:
valina [46]3 years ago
3 0

Answer:

The average current I supplied to the cars motor is 0.225 Amperes.

Explanation:

The mass of the toy car is given as, m = 0.6 kg

The toy car operates at a steady speed of, v =  3.43 m/s.

It achieves the steady speed after a time, t = 5.69 seconds.

The total kinetic energy of the car is given by,

E = \frac{1}{2} m v^2

= 0.5 × 0.6 × (3.43)^2

= 3.53 Joules

Since the efficiency of the motor is 30.6%  = 0.306

The electrical energy equivalent is supplied to motor  = \frac{3.53}{0.306}  = 11.54 Joules.

The electrical energy is given by P × t = I × V × t  = 11.54 Joules

P is the electric power where P = I × V where V is the voltage of the cell and is the average current, I.

Therefore we can write I × 9 × 5.69 = 11.54 Joules.

So the average current I = \frac{11.54}{9 \times 5.69 } = 0.225 Amperes.

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sp2606 [1]

Answer:

5.2941176471 kg or 5294.1 grams

Explanation:

g.p.e= mgh

g.p.e/gh=m

180j/10×3.4= m

180/34= m

5.2941 kg= m

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D Because If Your Going To Have A Contest Its Ganna Have To Be The Same Objectives For Both Contenders 
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3 years ago
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Norma-Jean [14]
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If a net force applied to an object is equal to zero, then the forces that are acting on an object are considered.
hjlf

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The mass will accelerate. Balanced Forces: When forces are in balance, acceleration is zero. Velocity is constant and there is no net or unbalanced force. A plane will fly at constant velocity if the acceleration is zero.

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A uranium nucleus is traveling at 0.94 c in the positive direction relative to the laboratory when it suddenly splits into two p
Anettt [7]

Answer:

A   u = 0.36c      B u = 0.961c

Explanation:

In special relativity the transformation of velocities is carried out using the Lorentz equations, if the movement in the x direction remains

     u ’= (u-v) / (1- uv / c²)

Where u’ is the speed with respect to the mobile system, in this case the initial nucleus of uranium, u the speed with respect to the fixed system (the observer in the laboratory) and v the speed of the mobile system with respect to the laboratory

The data give is u ’= 0.43c and the initial core velocity v = 0.94c

Let's clear the speed with respect to the observer (u)

      u’ (1- u v / c²) = u -v

      u + u ’uv / c² = v - u’

      u (1 + u ’v / c²) = v - u’

      u = (v-u ’) / (1+ u’ v / c²)

Let's calculate

      u = (0.94 c - 0.43c) / (1+ 0.43c 0.94 c / c²)

      u = 0.51c / (1 + 0.4042)

      u = 0.36c

We repeat the calculation for the other piece

In this case u ’= - 0.35c

We calculate

       u = (0.94c + 0.35c) / (1 - 0.35c 0.94c / c²)

       u = 1.29c / (1- 0.329)

       u = 0.961c

6 0
3 years ago
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