When we balance the given equation
POCl₃(g) ⇄ PCl₃(g) + O₂(g)
We will get
2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)
Solution:
Balancing the given equation
POCl₃(g) ⇄ PCl₃(g) + O₂(g)
Balancing the number of O
2POCl₃(g) ⇄ PCl₃(g) + O₂(g)
Balancing the number of P and Cl
2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)
We get the balanced equation
2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)
The reaction quotient will be
Qc = [product] / [reactant]
Qc = [PCl₃(g) + O₂(g)] / [POCl₃(g) ]
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Answer:
You cannot make observations if you are 57 seconds late into the lab.
Explanation:
The atomic nucleus can split by decay into 2 or more particles as a result of the instability of its atomic nucleus due to the fact that radioactive elements possess an unstable atomic nucleus.
Now, the primary particles which are emitted by radioactive elements in order to make them decay are alpha, beta & gamma particles.
The half life equation is;
N_t = N₀(½)^(t/t_½)
Where:
t = duration of decay
t_½ = half-life
N₀ = number of radioactive atoms initially
N_t = number of radioactive atoms remaining after decay over time t
We are given;
t = 57 secs
N₀ = 100 g
Now, half life of Nitrogen-16 from online sources is 7.2 seconds. t_½ = 7.2
Thus;
N_t = 100(1/2)^(57/7.2)
N_t = 0.4139g
We are told that In order to make observations, you require at least .5g of material.
The value of N_t you got is less than 0.5g, therefore you cannot make observations if you are 57 seconds late.
<span>The notation is not written in the correct order as the 4s subshell should appear before the 3d subshell.
</span>The correct order in an electron configuration would be:
1s , 2s , 2p , 3s , 3p , 4s , 3d , 4p , 5s , 4d , 5p , 6s , 4f , 5d , 6p ,..
So, for germanium the electronic configuration should be;
1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d¹⁰ 4p²
Answer:
The answer is C, both krypton and neon.
Explanation:
I got the answer wrong and my teacher told me that c is the right answer choice
