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tatyana61 [14]
3 years ago
5

8. When rubidium and fluorine combine to produce the compound RbF, che ions

Chemistry
1 answer:
skelet666 [1.2K]3 years ago
8 0

Answer:

The answer is C, both krypton and neon.

Explanation:

I got the answer wrong and my teacher told me that c is the right answer choice

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Balance the following Chemical Equation:<br> NaBr +CaCl2-&gt; NaCl+ CaBr2
frozen [14]
First write all of the compounds/atoms in either side then fill in existing values and balance


Na- 1
Br- 1
Ca- 1
Cl- 2

Na- 1
Cl- 1
Ca-1
Br-2

Balance to get

2NaBr+CaCl2=2NaCl+CaBr2
7 0
3 years ago
What specific electrophile does benzene attack when it undergoes nitration??
Deffense [45]
<span><span>The reaction is as follows:
        C6H6   </span>+   HNO3   +      H2SO4     ------------> </span>C6H5NO2<span>   +   H</span>2<span>O
(BENZENE) (NITRIC ACID)(CATALYST)
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7 0
3 years ago
Use the given data at 500 K to calculate ΔG°for the reaction
Anton [14]

Answer : The  value of \Delta G^o for the reaction is -959.1 kJ

Explanation :

The given balanced chemical reaction is,

2H_2S(g)+3O_2(g)\rightarrow 2H_2O(g)+2SO_2(g)

First we have to calculate the enthalpy of reaction (\Delta H^o).

\Delta H^o=H_f_{product}-H_f_{reactant}

\Delta H^o=[n_{H_2O}\times \Delta H_f^0_{(H_2O)}+n_{SO_2}\times \Delta H_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta H_f^0_{(H_2S)}+n_{O_2}\times \Delta H_f^0_{(O_2)}]

where,

\Delta H^o = enthalpy of reaction = ?

n = number of moles

\Delta H_f^0 = standard enthalpy of formation

Now put all the given values in this expression, we get:

\Delta H^o=[2mole\times (-242kJ/mol)+2mole\times (-296.8kJ/mol)}]-[2mole\times (-21kJ/mol)+3mole\times (0kJ/mol)]

\Delta H^o=-1035.6kJ=-1035600J

conversion used : (1 kJ = 1000 J)

Now we have to calculate the entropy of reaction (\Delta S^o).

\Delta S^o=S_f_{product}-S_f_{reactant}

\Delta S^o=[n_{H_2O}\times \Delta S_f^0_{(H_2O)}+n_{SO_2}\times \Delta S_f^0_{(SO_2)}]-[n_{H_2S}\times \Delta S_f^0_{(H_2S)}+n_{O_2}\times \Delta S_f^0_{(O_2)}]

where,

\Delta S^o = entropy of reaction = ?

n = number of moles

\Delta S_f^0 = standard entropy of formation

Now put all the given values in this expression, we get:

\Delta S^o=[2mole\times (189J/K.mol)+2mole\times (248J/K.mol)}]-[2mole\times (206J/K.mol)+3mole\times (205J/K.mol)]

\Delta S^o=-153J/K

Now we have to calculate the Gibbs free energy of reaction (\Delta G^o).

As we know that,

\Delta G^o=\Delta H^o-T\Delta S^o

At room temperature, the temperature is 500 K.

\Delta G^o=(-1035600J)-(500K\times -153J/K)

\Delta G^o=-959100J=-959.1kJ

Therefore, the value of \Delta G^o for the reaction is -959.1 kJ

3 0
3 years ago
What is the lewis structure for al?
bogdanovich [222]
The abbreviation Al, with one dot on top of the abbreviation, one on the left, one on the right.
8 0
3 years ago
What is the acceleration of an object that goes from 3 m/s to 5 m/s in 8 s?
nikdorinn [45]

Answer: 0.25m/s2

Explanation:

Acceleration is change in velocity with time

V = final velocity = 5m/s

U =Initial velocity = 3m/s

t = time = 8s

a = Acceleration =?

a = V — U / t

a = (5 — 3) / 8

a = 2/8

a = 0.25m/s2

8 0
3 years ago
Read 2 more answers
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